To determine if (3x - 3y = 21) and (5x + 4y = 24) have a solution, we can solve the system of equations. Rearranging the first equation gives (x - y = 7) or (x = y + 7). Substituting this into the second equation allows us to find values for (x) and (y). Solving the resulting equation will reveal whether there are specific values that satisfy both equations simultaneously.
9x-3y=63 7x-3y=45 -3y=63-9x -y=21-3x y=-21+3x 7x-3(-21+3x)=45 7x+63+9x=45 7x+9x=45-63 16x=-18 x=-1.125 y=-21+3(-1.125) y=-24.375 (-1.125,-24.375)
2x + 3y = 17 3x + 4y = 24 (2x + 3x) + (3y + 4y) = (17 + 24) 5x + 7y = 41
70000000y=35t
The slope is -1. 3x+3y=12 Subtract 3x 3y=-3x+12 Divide by 3 y=-x+4
2X + 3Y = 24 subtract 2X from both sides 3Y = - 2X + 24 divide both sides by 3 Y = - 2/3X + 8 slope(m) = - 2/3
Which system of inequalities has no solution?A.y > 3x - 1y < 3x - 3B.y > 3x + 3y < 3x + 7C.y > -1y < 2y > 2x - 3re...
5000y
9x-3y=63 7x-3y=45 -3y=63-9x -y=21-3x y=-21+3x 7x-3(-21+3x)=45 7x+63+9x=45 7x+9x=45-63 16x=-18 x=-1.125 y=-21+3(-1.125) y=-24.375 (-1.125,-24.375)
2x + 3y = 17 3x + 4y = 24 (2x + 3x) + (3y + 4y) = (17 + 24) 5x + 7y = 41
70000000y=35t
3x-3y?
No, it has an infinite number of solutions. The coordinates of each and every point on the line 3x + 2y + 4 = 0 is a solution.
If you mean the straight line equation: 3y-9x = 24 then y = 3x+8
41
Dont trip B****
6
The slope is -1. 3x+3y=12 Subtract 3x 3y=-3x+12 Divide by 3 y=-x+4