To determine if (3x - 3y = 21) and (5x + 4y = 24) have a solution, we can solve the system of equations. Rearranging the first equation gives (x - y = 7) or (x = y + 7). Substituting this into the second equation allows us to find values for (x) and (y). Solving the resulting equation will reveal whether there are specific values that satisfy both equations simultaneously.
To determine if (4, -3) is a solution to the system, we need to substitute x = 4 and y = -3 into both equations. For the first equation (3x - 3y = 21): (3(4) - 3(-3) = 12 + 9 = 21) (True) For the second equation (5x + 4y = 24): (5(4) + 4(-3) = 20 - 12 = 8) (False) Since (4, -3) does not satisfy the second equation, it is not a solution to the system.
9x-3y=63 7x-3y=45 -3y=63-9x -y=21-3x y=-21+3x 7x-3(-21+3x)=45 7x+63+9x=45 7x+9x=45-63 16x=-18 x=-1.125 y=-21+3(-1.125) y=-24.375 (-1.125,-24.375)
2x + 3y = 17 3x + 4y = 24 (2x + 3x) + (3y + 4y) = (17 + 24) 5x + 7y = 41
70000000y=35t
The slope is -1. 3x+3y=12 Subtract 3x 3y=-3x+12 Divide by 3 y=-x+4
To determine if (4, -3) is a solution to the system, we need to substitute x = 4 and y = -3 into both equations. For the first equation (3x - 3y = 21): (3(4) - 3(-3) = 12 + 9 = 21) (True) For the second equation (5x + 4y = 24): (5(4) + 4(-3) = 20 - 12 = 8) (False) Since (4, -3) does not satisfy the second equation, it is not a solution to the system.
Which system of inequalities has no solution?A.y > 3x - 1y < 3x - 3B.y > 3x + 3y < 3x + 7C.y > -1y < 2y > 2x - 3re...
9x-3y=63 7x-3y=45 -3y=63-9x -y=21-3x y=-21+3x 7x-3(-21+3x)=45 7x+63+9x=45 7x+9x=45-63 16x=-18 x=-1.125 y=-21+3(-1.125) y=-24.375 (-1.125,-24.375)
5000y
2x + 3y = 17 3x + 4y = 24 (2x + 3x) + (3y + 4y) = (17 + 24) 5x + 7y = 41
70000000y=35t
3x-3y?
No, it has an infinite number of solutions. The coordinates of each and every point on the line 3x + 2y + 4 = 0 is a solution.
If you mean the straight line equation: 3y-9x = 24 then y = 3x+8
41
Dont trip B****
6