Q: Is 474 divisible by 3

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Yes: 474 Ã· 3 = 158

No because it will have a remainder of 4

All numbers divisible by 3, 221, 381, 474, 922 & 726 are multiples of their lowest common multiple which is: 3 = 3 221 = 13 x 17 381 = 3 x 127 474 = 2 x 3 x 79 922 = 2 x 461 726 = 2 x 3 x 112 lcm = 2 x 3 x 112 x 13 x 17 x 79 x 127 x 461 = 736242224998 ie 736242224998, 1484193849996, 2226290774994, 2968387699992, 3710484624990, ...

As a product of its prime facors: 2*3*79 = 474

If x is an integer divisible by 3, is x squared divisible by 3?

Related questions

Yes: 474 Ã· 3 = 158

Some examples are... 381 474 726

1, 2, 3, 4, 6, 12, 79, 158, 237, 316, 474, 948

1, 2, 3, 6, 9, 18, 79, 158, 237, 474, 711, 1422.

No because it will have a remainder of 4

474

474 is an even number, so it can be branched into 2 and 237 The sum of digits in 237 (2+3+7 = 12) is divisible by 3, so the next branch should be 3 and 79. Since 79 is a prime number, you cannot simplify it anymore, thus your final branches will be 2, 3, and 79. 474 2 x 237 2 x 3 x 79

All numbers divisible by 3, 221, 381, 474, 922 & 726 are multiples of their lowest common multiple which is: 3 = 3 221 = 13 x 17 381 = 3 x 127 474 = 2 x 3 x 79 922 = 2 x 461 726 = 2 x 3 x 112 lcm = 2 x 3 x 112 x 13 x 17 x 79 x 127 x 461 = 736242224998 ie 736242224998, 1484193849996, 2226290774994, 2968387699992, 3710484624990, ...

In revision 474 :3

The positive integer factors of 474 are: 1, 2, 3, 6, 79, 158, 237, 474

1, 2, 3, 6, 79, 158, 237, 474.

2 x 3 x 70 = 474