It is 4xy.
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
(x + 3)(x + 4y)
It is 4xy.
It is 4xy.
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
It is 4xy.
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
(x + 3)(x + 4y)
the difference between 2x2 +4xy-3 and x2-2xy-4 is?
It is 4xy.
-1
3x2y - 4xy + 4x
(2x2+4xy-3)-(x2-2xy-4)Answer: x2+6x+1