507 is composite. It is divisible by 3, 13, 39, and 169, as well as by 1 and itself.
i do not know the answer please show your work for i could copy it
169
The prime factorization of 507 is 3 x 13 x 13
if the number is a 2 or more diget number, you add up all of the numbers in the number and when you have the sum, if the sum is divisible by 3 , the whole number is divisible by three EX. 123=6, 6 is divisible by 3 so 123 is divisible by three 447=15 is divisible by 3 so 447 is divisible by 3 989=26 is *NOT* divisible by 3 so 989 is not divisible by three this truly does work for every single number
1521/3 = 507
507 is composite. It is divisible by 3, 13, 39, and 169, as well as by 1 and itself.
i do not know the answer please show your work for i could copy it
7, 31, 49, 217.
Yes, all numbers are divisible by 3. However, if you mean whether it will divide by 3 exactly (without any remainder) to give a whole number result (an integer), then the answer is no. 1522/3 = 507 1/3 (five hundred and seven and a third).
169
The factors of 507 are: 1, 3, 13, 39, 169, and 507. The prime factors of 507 are: 3 and 13.
3 x 507 x 2 equals 3,042
For a number to be divisible by 3, its digit sum has to be divisible by 3. For a number not to be divisible by 2, the last digit must be a 1,3,5,7 or 9. Using these rules, the numbers between 500 and 600 that divide by 3 but not 2 become clear: 501, 507, 513, 519, 525, 531, 537, 543, 549, 555, 561, 567, 573, 579, 585, 591 and 597
The divisibility rule of 3 is that you add the digits together and then if the number you come up with is divisible by 3, then the number itself is divisible by 3. In this instance, 5 + 8 + 5 = 18/3 = 6, therefore, 585 is divisible by 3.
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.
1 + 5 + 6 + 3 = 15 15 is a multiple of 3. 15603 is a multiple of 3. That makes it composite.