Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
Yes, 1255 is divisible by 5, and any number that ends in 5 is divisible by 5.
no. Here is a rule to learn- If a number is divisible by 5, it must end in 0 or 5. If it does not, it is not divisible by 5. Numbers that end in 1,2,3,4,6,7,8,9 are NOT divisible by 5. (Conversely,) if the number does end in 0 or 5 , it is divisible by 6.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
435 with remainder 5.
5225 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 12 factors of 5225 are 1, 5, 11, 19, 25, 55, 95, 209, 275, 475, 1045, and 5225.The factor pairs of 5225 are 1 x 5225, 5 x 1045, 11 x 475, 19 x 275, 25 x 209, and 55 x 95.The proper factors of 5225 are 1, 5, 11, 19, 25, 55, 95, 209, 275, 475, and 1045 or,if the definition you are using excludes 1, they are 5, 11, 19, 25, 55, 95, 209, 275, 475, and 1045.The prime factors of 5225 are 5, 5, 11, and 19.Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The 3 distinct prime factors (listing each prime factor only once) of 5225 are 5, 11, and 19.The prime factorization of 5225 is 5 x 5 x 11 x 19 or, in index form (in other words, using exponents), 52 x 11 x 19.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
YES. 285 is divisible by 5. A number is divisible by 5 if it ends with 0 or 5
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
Yes, 1255 is divisible by 5, and any number that ends in 5 is divisible by 5.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
No, because 1 is not evenly divisible by 5. However, all numbers divisible by 5 are divisible by 1.
5/5715 = 0.000874891 5 is not evenly divisible by 5715. However, 5715 is divisible by 5. (If a number ends in 5 or 0 it is divisible by 5.) 5715/5 = 1143
5 is not divisible by 1260. 1260 is divisible by 5 because 1260 is a multiple of 5.
no. Here is a rule to learn- If a number is divisible by 5, it must end in 0 or 5. If it does not, it is not divisible by 5. Numbers that end in 1,2,3,4,6,7,8,9 are NOT divisible by 5. (Conversely,) if the number does end in 0 or 5 , it is divisible by 6.