An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 56 is an even number.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 56 is an even number.
37, surely? Odd number and all.
There is no set of odd numbers whose product is 56 since the latter is even.
Actually the problem does not have a solution with the constraint that the two numbers are consecutive integers. With consecutive integers, one of the integers will be odd and the other one even. An even plus an odd always equals an odd, and you want them to add up to 56, which is an even number. 27.5 + 28.5= 56. steps shown below: x+ (x+1)=56 2x+1 = 56 2x= 56-1 2x= 55 x=55/2 x=27.5 second number is x +1= 27.5+1= 28.5
No.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 56 is an even number.
25 + 56 = 81 81 = odd number
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 56 is an even number.
no it can be divided by 2 56 is a very odd number, considering the fact that it has been used by many scientists. stupid questions deserve stupid answers.
The odd prime factor of 56 is: 7
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 56 is an even number.
37, surely? Odd number and all.
The only odd prime factor of 56 is: 7
56 = 2^3*7 so the only odd factors (apart of 1) is 7.
There is only one odd prime factor in 56, which is 7.
There is no set of odd numbers whose product is 56 since the latter is even.