ya i will solve this question by taking assumptions if we observe the question easily identified the larger number is greater than smaller number by 6 and one thing is the sum of two numbers is 3 times their difference from this information we clearly says sum is divided by 3 so if we take smaller number 1 larger number 7(add 6) (1+6)=3(5) and now smaller number 2 larger number 8 (2+8)=3(6) : : : take smaller number 6 larger number 12 this is the correct answer 6+12=3(6)
0.5 larger the number the smallest its worth and 0.67 is in the hundredths which is small
600
A smaller number is never divisible by a larger number, so no, it is not.
12 Let x represent the smaller number and y the larger number. From the problem, we have two equations: x+y=3(y-x) y=x+6 Now solve for x: x+(x+6)=3((x+6)-x) 2x+6=18 x=12 Now use this to solve for y: y=x+6=6+6=12
4 is larger.
ya i will solve this question by taking assumptions if we observe the question easily identified the larger number is greater than smaller number by 6 and one thing is the sum of two numbers is 3 times their difference from this information we clearly says sum is divided by 3 so if we take smaller number 1 larger number 7(add 6) (1+6)=3(5) and now smaller number 2 larger number 8 (2+8)=3(6) : : : take smaller number 6 larger number 12 this is the correct answer 6+12=3(6)
No, the opposite of -6 would be 6, which is larger.
The sum of the numbers is 240. If one number is 5 times as big as the other then 240 must be divided by 6. 240/6 = 40. The smaller number must be this while the larger number is 5 times the size. Small number = 40 Larger number = 40 * 5 = 200
0.5 larger the number the smallest its worth and 0.67 is in the hundredths which is small
0.4 the larger the number the smallest its worth and 0.45 is in the hundredths which is small
The largest number is 45, which is a whole number. The decimal 0.55 is only a small part of a whole number.
Smaller number = x Larger number = 2x x+2x=18. 3x=18 x=6 The numbers are 6 and 12.
6
42
600
A smaller number is never divisible by a larger number, so no, it is not.