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How do yo find the width of a rectangle if the perimeter is 334 and the length is 96?
we have the formula to find perimeter of the rectangle i.e. perimeter = 2(l+b) where l = length b = breadth substitute l=96 and perimeter = 334,we get 334 = 2(96+b) 334/2=96+b, 167 = 96 + b b = 167-96 =71. b = breadth of the given rectangle is 71.
What percent of 61 is 72?
Percentage = Base x Rate ( P= B x R ) Given: P = 61 ; B = 71 ; R = ? 61 = 71 x R 61 / 72 = R 0.85 = R Therefore 0.85 in percent form 85%. 61 is 85% of 72
What is the perimeter of a triangle when an angle of 57 degrees is opposite to a side of 14.5 inches and has another angle of 71 degrees?
The sum of tthe angles of a triangle is 180° which means the third angle is 180° - (57° + 71°) = 52° The sine rule gives: a/sin A = b/sin B = c / sin C where side a is opposites angle A, etc. The sine rule can be used to find the lengths of the other two sides when the angles are all known and one side length is known. Let angle A = 57°, then side a = 14.5 in. Let angle B = 71° and angle C = 52° Using the sine rule: a/sin A = b/ sin B → b = a × sin B/sin A Similarly, c = a × sin C/sin A → The perimeter = a + b + c = a + a × sin B/sin A + a × sin C/sin A = a(1 + sin B/sin A + sin C/sin A) = 14.5 in × (1 + sin 71° / sin 57° + sin 52° / sin 57°) ≈ 44.47 in ≈ 44.5 in
What is 30 percent of 71?
30% of 71= 30% * 71= 0.3 * 71= 21.3
What is 40 percent of 71?
40% of 71 = 40% * 71 = 0.4 * 71 = 28.4
