Just add up the digits and if that sum is divisible by 9 then the original number is divisible by 9. Example 729 = 7+2+9 = 18 (18 is divisible by 9 therefore 729 is divisible by 9) 123456789 = 1+2+3+4+5+6+7+8+9 = 45 (45 is divisible by 9 therefore 123456789 is divisible by 9)
Since the sum, 18, of the digits of 729 is divisible by 3, 18 = 3 x 6, then 729 is divisible by 3.
No.
It is 9*9*9 = 729
729
729 is divisible evenly by 9, but not evenly by 8, quotient is 91, remainder is 1
729 is divisible by 1, 3, 9, 27, 81, 243, 729.
No.
It is divisible by 9.
Just add up the digits and if that sum is divisible by 9 then the original number is divisible by 9. Example 729 = 7+2+9 = 18 (18 is divisible by 9 therefore 729 is divisible by 9) 123456789 = 1+2+3+4+5+6+7+8+9 = 45 (45 is divisible by 9 therefore 123456789 is divisible by 9)
Multiples of 729.
Since the sum, 18, of the digits of 729 is divisible by 3, 18 = 3 x 6, then 729 is divisible by 3.
No.
yes!
Answer: -9 -9 * -9 = 81 81 * -9 = -729
It is 9*9*9 = 729
93=9*9*9. 9*9 is 81, and 81*9 is 729. 93=729.