To determine if the lengths 7, 14, and 16 form a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) equals the sum of the squares of the other two sides. Here, the longest side is 16. Calculating, we get (16^2 = 256) and (7^2 + 14^2 = 49 + 196 = 245). Since (256 \neq 245), the sides 7, 14, and 16 do not form a right triangle.
56 sq. units A = 1/2 Base x Height A = 1/2 (7 x 16)
56 square units
No. 42 + 72 = 16 + 49 = 65 whereas 102 = 100 Since these two are unequal, by Pythagoras' Theorem, the triangle cannot be right angled.
The least common multiple of 7 , 14 , 16 = 112
½ × 14 × 16 = (½ × 14) × 16 = 7 × 16 = 112.
56 sq. units A = 1/2 Base x Height A = 1/2 (7 x 16)
The area of a right triangle that has legs 7 cm and 4 cm long can be calculated using the fact that a right triangle is half of a rectangle. The area of a rectangle is l*h, so the area of a right triangle is l*h/2. In this case, the area is 14 cm^2.
56 square units
No. 42 + 72 = 16 + 49 = 65 whereas 102 = 100 Since these two are unequal, by Pythagoras' Theorem, the triangle cannot be right angled.
is it a right triangle if the measure is 5 7 and 9
4 * 7 = 28 28/2 = 14 sq cm
The least common multiple of 7 , 14 , 16 = 112
½ × 14 × 16 = (½ × 14) × 16 = 7 × 16 = 112.
7/8 of 16 is 14.
7/8 of 16 is 14.
231 ÷ 16 = 14 remainder 7
7, 14, 21, and 28.