Q: Is 7k plus 0 equals 7k a multiplicative identity?

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It simplifies to 7k = 49 which gives k = 7.

Same as subtracting 6 from 7 = K

-6K+7K=1K or K

k + 6k - 13 = 177k = 30k = 30/7k = 4.2857

-6k + 7k = k

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3k-5=7k+73k-7k=7+5-4k=12k=-3

It simplifies to 7k = 49 which gives k = 7.

Same as subtracting 6 from 7 = K

-6K+7K=1K or K

k + 6k - 13 = 177k = 30k = 30/7k = 4.2857

Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution. The most that you can do is: 13p = 31-7k so that p = (31-7k)/13

35k2 - 22k + 3 = 0 35k2 - 15k - 7k + 3 = 0 5k(7k - 3) - (7k - 3) = 0 (5k - 1)(7k - 3) = 0 5k -1 = 0 or 7k - 3 = 0 5k = 1 or 7k = 3 k = 1/5 or k = 3/7

-6k + 7k = k

1k

7(k + 5)(k - 4)

7k + 4 + 4k - 9 - 5k (7k + 4k - 5k) + (4 - 9) 6k + -5 6k - 5

26-7k=6k First, add 7k to get k on one side. 26-7k+7k=6k+7k 26=13k Divide both sides by 13 to get k by itself. 26/13=13k/13 2=k The answer is 2.