9 and 64 are square numbers but 8 is not.
Yes because 3*3 = 9 and 8*8 = 64
8 and 9 because square root of 64=8 and square root of 81=9
Any number between 64 & 81 inclusive.
There are 8 square numbers between 0 and 100. 4, 9, 16, 25, 36, 49, 64, 81
The answer depends on what you mean by higher. 81 is bigger than 64. But the square roots of 81 are -9 and +9 while the square roots of 64 are -8 and +8. You then have -9 < -8 so sqrt(81) < sqrt(64) -9 < 8 so sqrt(81) < sqrt(64) -8 < 9 so sqrt(64) < sqrt(81) 8 < 9 so sqrt(64) < sqrt(81) Take your pick!
Yes because 3*3 = 9 and 8*8 = 64
8 and 9 because square root of 64=8 and square root of 81=9
64 and 81 are squares of whole numbers. 64 is the square of 8 (8x8=64) and 81 is the square of 9 (9x9=81).
The square root of 72 is between 8 and 9 BECAUSE 8 squared is 64 9 squared is 81 since 72 lies between 64 and 81, then the square root must lie between 8 and 9
The square numbers between 40 and 90 are: 49, 64, 81. This is because 7 squared = 49. 8 sqd. = 64. 9 sqd. = 81.
These are square numbers. 81 = 9 x 9 64 = 8 x 8 49 = 7 x 7 36 = 6 x 6
Any number between 64 & 81 inclusive.
There are 8 square numbers between 0 and 100. 4, 9, 16, 25, 36, 49, 64, 81
There are infinitely many solutions:The square of 8 is 64.The square of 9 is 81. Therefore, the square root of ANY NUMBER between 64 and 81 is between 8 and 9.
8 & 9. 82 = 64 92 = 81
The answer depends on what you mean by higher. 81 is bigger than 64. But the square roots of 81 are -9 and +9 while the square roots of 64 are -8 and +8. You then have -9 < -8 so sqrt(81) < sqrt(64) -9 < 8 so sqrt(81) < sqrt(64) -8 < 9 so sqrt(64) < sqrt(81) 8 < 9 so sqrt(64) < sqrt(81) Take your pick!
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