Probably not.
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There's only one solution. [ x = -7 ]
-7
y=3x-7 y=-x+1 We're looking for when their x=x and y=y, so set the problems equal to each other. 3x-7=-x+1 3x+x-7=x-x+1 4x-7=1 4x-7+7=1+7 4x=8 4x/4=8/4 x=2 Let x=2 and solve for y in one of the equations. y=-(2)+1 y=-1 The solution is:(2,-1)
8+-1= 7 x=-1
8 x [1 + (7 - 5)] = 8 x [1 + 2] = 8 x 3 = 24
Of course, x-1=8 is a solution. Any equation which results with the variable value as 9 is ur answer. For eg: x = 9 / x-9 = 0 1 - x = -8 / x-1 = 8 x-2 = 7 / 2-x = -7 Any, any such equation will be your answer(correct answer). Enjoy
It could be either, depending on what x equals. If x = 9, 8 will solve the first one. If x = 1, 8 will solve the second one.
There's only one solution. [ x = -7 ]
-7
y=3x-7 y=-x+1 We're looking for when their x=x and y=y, so set the problems equal to each other. 3x-7=-x+1 3x+x-7=x-x+1 4x-7=1 4x-7+7=1+7 4x=8 4x/4=8/4 x=2 Let x=2 and solve for y in one of the equations. y=-(2)+1 y=-1 The solution is:(2,-1)
8+-1= 7 x=-1
short answer -1 and -7 long worked answer let x = one of the integers let y = the other integer x+y = -8 xy = 7 solve for y y = -8 - x plug y in x(-8 - x) = 7 rearrange -x^2 - 8x - 7 = 0 divide both sides by -1 x^2 + 8x + 7 = 0 factor (x + 7)(x + 1) = 0 x = -1, -7 y = -8 - x so y = -8 + 1 = -7 or -8 + 7 = -1 so when x = -1, y = -7 when x = -7, y = -1
One solution is, 7 + (7/(5 + 2)) = 7 + 1 = 8. Or, 2 + ((5 + 7)/2) = 2 + 6 = 8. Or, (7 x 5) - 27 = 35 - 27 = 8. Or, 2(7 - 5) x 2 = 22 x 2 = 8 No doubt there are many other solutions.
8 x [1 + (7 - 5)] = 8 x [1 + 2] = 8 x 3 = 24
If X - 8 = -1 then X = -1 +8 Therefore X = 7
The answer is A 1 x 10^(-6)
1/8 x 7 is 7/8