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What is 11 divided by 2 with remainder?
5.5
What is 2 divided by 767?
0.0026
What is 2 divide by -2 equals what?
4
If R1 equals 2 and R2 equals 4 in a 12 volt series circuit what is the total circuit resistance?
Series circuit? Add 'em!
Can you divide 633 into 2?
No it equals 316.5
What is the remainder when you divide 15 by 7?
15 divided by 7 = 2 R1 (Two remainder one) As a decimal, it is 2.14285714
Equation x2 plus Bx plus c equals 0 has 5 as the sum of its roots and 15 as the sum of the squares of its roots The value of 'c' is equals?
x2 - (-b/a)x + (c/a) = 0 or x2 - (sum of the roots)x + (product of the roots) = 0 Let the roots be r1 and r2. So we have: r1 + r2 = 5 (r1)2 + (r2)2 = 15 r1 = 5 - r2 (express r1 in term of r2) (5 - r2)2 + (r2)2 = 15 25 - 10r2 + (r2)2 + (r2)2 = 15 2(r2)2 - 10r + 25 = 15 (subtract 15 to both sides) 2(r2)2 - 10r + 10 = 0 (divide by 2 to both sides) (r2)2 - 5r + 5 = 0 (use the quadratic formula) r2 = [-b + &- sq root of (b - 4ac)]/2a r2 = {-(-5) + &- sq root of [(-5)2 - 4(1)(5)]}/2(1) = [5 + &- sq root of (25 - 20)]/2 = (5 + &- sq root of 5)/2 r1 = 5 - r2 r1 = 5 - (5 + &- sq root of 5)/2 Thus, when r2 = (5 + sq.root of 5)/2, r1 = (5 - sq.root of 5)/2 or vice versa. Since the given equation is x2 + bx + c = 0, a = 1, then c equals to the product of roots. So that, c = (r1)(r2) = [(5 - sq.root of 5)/2][(5 + sq.root of 5)/2] = [52 - (sq.root of 5)2]/4 = 5
Why is 2 divide 10 equals 2?
It is not. 2/10 = 0.2
What is roman numeral of 2 767 989?
2 = II 767 = DCCLXVII 989 = CMLXXXIX
What does 700 divide by 2 equals?
350
What is 200 divide by 2 equals?
100
What is the 0 power equals what?
Any number raised to the power of zero equals 1. For example, start out with 2^3 = 8. Then divide by 2 and get 2^2=4. Divide by 2 again: 2^1=2. Divide by two again: 2^0=1.
