The short answer is no.
90 cannot be cleanly divided by 7, it would leave a remainder of 6. You could fit 7 into 90, 12 times - which would equal 84.
90 will, however, cleanly divide with no remainder against all the other numbers you listed; 2 (45 times), 3 (30 times), 5 (18 times), 9 (10 times), and 10 (9 times).
90 is divisible by: 1 2 3 5 6 9 10 15 18 30 45 90.
The number 90 is divisible by both 2 and 3.
90 is the correct answer
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
90 is divisible by 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, and 90. Because 1x90=90 2x45=90 3x30=90 5x18=90 and so on, try starting to divide by the lowest numbers and work your way up.
90 is divisible by: 1 2 3 5 6 9 10 15 18 30 45 90.
The number 90 is divisible by both 2 and 3.
90
as 9 is made of 3 times 3 so any number (such as 90) which is divisible by 9 will also be divisible by 3 and the answer will be 3 times bigger so 90/9 is 10 then 90/3 = 30 which is 10 x 3 Example: same for any number that is divisible by 14 will also be divisible by 7 (or also 2) as 14 = 7 x 2 or divisible by say 50 is also divisible by 5 or 10 as 50 = 5 x 10 and so on ...
2,3,5,6,9,10. Not by 4.
90
90.
Any multiple of 90.
1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90
90 is divisible by 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90.
90
90 is the correct answer