That would be 999.
999.
0
3 and 333 **************** I would like to add 1 and also 9 (999 ÷ 9 = 111) to the above list.
105, 111, 117 and just keep adding 6 until you get to 999.
That would be 999.
Between 100 and 999 there are 448.
1000 is the smallest 4 digit number but of the two factors, it is only divisible by 2. As 999 is obviously divisible by 3 then 999 + 3 = 1002 is also divisible by 3 and, as an even number, is also divisible by 2. The answer is 1002
999.
0
999
999 is 333 :) (dividedby three)
3 and 333 **************** I would like to add 1 and also 9 (999 ÷ 9 = 111) to the above list.
No.
105, 111, 117 and just keep adding 6 until you get to 999.
The largest 3-digit number is 999. To check if it is a multiple of 3, you can sum the digits: 9 + 9 + 9 = 27, which is divisible by 3. Therefore, 999 is the largest 3-digit number that is a multiple of 3.
Oh, dude, let me break it down for you. So, to find the numbers divisible by both 3 and 4, you need to find the numbers divisible by their least common multiple, which is 12. From 100 to 999, every 12th number is divisible by 12. So, you just need to find how many multiples of 12 are there between 100 and 999. It's like a piece of cake, you got this!