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If C is Celsius temperature and F is the Fahrenheit temperature, the relation between them is:
F=(9/5)C+32
You can graph that into a linear function.
And since the line y=x (this is when y is Celsius) and y=(9/5)x+32 (this is when y is Fahrenheit) have different slopes, they are going to meet once on the graph.
(Different slopes mean they are not parallel and only parallel lines don't meet each other in a 2D. And the point they meet is the point where C and F are equal. And if the temperature is hotter than that, F>C, and if the temperature is colder than that, C>F)
x=(9/5)x+32
So x=-40 (C=-40, F=-40)
Therefore if it's hotter than -40°C (or -40°F), Fahrenheit is bigger than Celsius (when it's the same amount of heat). And if it's colder than -40°C (or -40°F), Celsius is bigger than Fahrenheit (when it's the same amount of heat)
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When does Celsius and ferenhite is equal?
The relationship between Celsius and Fahrenheit is:c = (5 / 9) * (f - 32)So if they are equal, we can simply note that c and f are equal in that equation, and then solve it. Let' call them both "t":t = (5 / 9) * (t - 32)∴ t = (5t - 160) / 9∴ t = 5t/9 - 160/9∴ t - 5t/9 = -160/9∴ 4t/9 = -160/9∴ 4t = -160∴ t = -40So -40°F = -40°C
What is lesser value -20 or -10?
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What is greater than and lesser than?
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Kelvins= Celsius + 273.15 240-273.15= Celsius= -33.15C 468-273.15=Celsius= 149.85C
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0 degrees Celsius is a colder temperature than 40 degrees Celsius. 0 degrees Celsius is the freezing level for water. Any positive number above 0 degrees Celsius is a warmer temperature.
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39.5 degrees Celsius is equal to 103.1 degrees Fahrenheit.
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Oxygen is a gas at 25 degrees Celsius because its boiling point is -183 degrees Celsius, which is much lower than room temperature. At 25 degrees Celsius, oxygen molecules have enough kinetic energy to overcome intermolecular forces and exist in a gaseous state.
When does Celsius and ferenhite is equal?
The relationship between Celsius and Fahrenheit is:c = (5 / 9) * (f - 32)So if they are equal, we can simply note that c and f are equal in that equation, and then solve it. Let' call them both "t":t = (5 / 9) * (t - 32)∴ t = (5t - 160) / 9∴ t = 5t/9 - 160/9∴ t - 5t/9 = -160/9∴ 4t/9 = -160/9∴ 4t = -160∴ t = -40So -40°F = -40°C
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