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T1= t2= t3= t4= r=
t1 s1 b1 t1 s1 b2 t1 s2 b1 t1 s2 b2 t2 s1 b1 t2 s1 b2 t2 s2 b1 t2 s2 b2 t3 s1 b1 t3 s1 b2 t3 s2 b1 t3 s2 b2 TOTAL 12 combinations OR 2(3 x 2) = 12
The third law could be expressed as: If T1 = T2 and T2 = T3, then T1 = T3. Where T1 is the temperature of system (or object) 1. T2 is the temperature of system (or object) 2. T3 is the temperature of system (or object) 3. That may seem trivial from an algebraic standpoint but it has profound implications in thermodynamics because it helps define the meaning of temperature and thermal equilibrium.
The ratio of the quantity between two sets of time an equal period apart are the same. That is, the rate of growth over the same time is a constant. Suppose V(t) is the value of the variable V at time t. Then, if t1, t2, t3 and t4 are four times such that t2 - t1 = t4 - t3 then V(t2)/V(t1) = V(t4)/V(t3) whether V is compound interest or exponential growth.
The only factor is 2. 2*(t3 + 2t2 + 4x)