The conjugate base of H2SO3 is HSO3- and the conjugate acid is H3O+.
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H2SO3 can ionize in water to produce hydronium ions (H3O+) and sulfite ions (SO3^2-): H2SO3 + H2O → H3O+ + HSO3-. This reaction illustrates the acid-base behavior of sulfurous acid in water.
The equilibrium constant expression for H2SO3 is K = [H+]^2[HSO3-]/[H2SO3].
When HSO3- is added to water, it will dissociate into bisulfite ions (HSO3-) and hydrogen ions (H+). The bisulfite ions will react with water to form sulfurous acid (H2SO3).
HSO3- is the bisulfite ion, which is a conjugate base of sulfurous acid (H2SO3). It has a negative charge and consists of one hydrogen atom, one sulfur atom, and three oxygen atoms. Bisulfite ions are often used as reducing agents in various chemical reactions.
The chemical formula for hydrogen bisulfite is HSO3-.
Sulfur dioxide gas dissolves in water to form sulfurous acid (H2SO3). This reaction is reversible and the acid can further dissociate to release hydrogen ions (H+) and bisulfite ions (HSO3-).
When SO2 dissolves in water, it forms sulfurous acid (H2SO3). This acid is a weak acid that can dissociate into bisulfite ions (HSO3-) and hydrogen ions (H+).
When sulfur dioxide dissolves in water, it forms sulfurous acid (H2SO3) which can further dissociate into bisulfite ions (HSO3-) and sulfite ions (SO3^2-). This can lead to the formation of sulfurous acid solutions, which can be corrosive and may have a characteristic pungent odor.
When sulfur dioxide is dissolved in water, it forms sulfurous acid (H2SO3). This reaction can lead to the acidification of the water, lowering its pH. Sulfurous acid is a weak acid that can further react to form sulfite ions (SO3^2-) and bisulfite ions (HSO3^-).
The conjugate base of HSO3- is SO32-. This is formed when HSO3- donates a proton.