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Let the perimeter of the triangle MNO be x.Since the perimeters of similar polygons have the same ratio as any two corresponding sides, we have13/26 = 44/x (cross multiply)13x =1,144 (divide both sides by 13)x = 88Or since 13/26 = 1/2, the perimeter of the triangle MNO is twice the perimeter of the triangle HIJ, which is 88.
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Roman numerals shown in a chemical formula, indicate the oxidation number of theprincipal metal ion. e.g. Fe(II)SO4 ; Ferric Sulphate Fe(III)SO4 ; Ferrous sulphate. KMnO4 = KMn(VII)O4 , Potassium permanganate . The manganese is in oxidation state (VII) ' '7'.