Imagine that you have a list of 15 numbers for example. The mean is the average of those number. In other words, take the sum of all the numbers and divide by how many numbers there are (15 in this case). The median is the "middle number," and is found by arranging all the numbers in order of size and then picking the middle number. If you have 15 numbers, the 8th number is the middle one (there would then be seven smaller numbers and seven larger). If instead you have an even number of numbers, then you don't have a single middle number (you have two), and so you would take the average of the two middle ones (for example, if you have 16 numbers, you take the average value of the 8th and 9th numbers as the median). Whether the median or the mean is larger depends entirely on the specific list of number that you are analyzing.
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The Mean is the average of a given set of values. The Median is the value that has the same number of smaller values than the number of higher values, it is in the middle of them. In a symmetrical distribution the Mean is equal to the Median. In an asymmetrical distribution they have different value.
Yes, the median can be greater than the mean. It just depends on the values of the data. A simple series of 1,5,6 has 5 as the median, with a mean of 4.
A single number cannot have a range (other than 0), nor can it have a median that is different from its mean. A single number cannot have a range (other than 0), nor can it have a median that is different from its mean. A single number cannot have a range (other than 0), nor can it have a median that is different from its mean. A single number cannot have a range (other than 0), nor can it have a median that is different from its mean.
The mean is better than the median when there are outliers.