NO, lets take an example.. 24 is divided by 2 and 8 both.. but not by 16..
The number 32 is divisible by 1, 2, 4, 8, 16, and 32.
4 x 4 = 16 2 x 8 = 16 8 x 4 = 32 4 x 8 = 32...
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.
8, 4, 12, 16, etc.
Every other number: 8, 16, 24, 32, 40... No, a number can be divisible by 4 but not divisible by 8; an example is 12.
The number 32 is divisible by 1, 2, 4, 8, 16, and 32.
4 x 4 = 16 2 x 8 = 16 8 x 4 = 32 4 x 8 = 32...
Let's see . . .The only number we can find that equals 16 is . . . 16. It is divisible by 8, so that must be the answer.
If the number formed by the last three digits is divisible by 8. Alternatively, if the number is divisible by 2, the quotient is divisible by 2 and that quotient is divisible by 2.
* 8 * 16
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.
8, 4, 12, 16, etc.
Every other number: 8, 16, 24, 32, 40... No, a number can be divisible by 4 but not divisible by 8; an example is 12.
The digital root (sum of digit) must be divisible by 9, and the number formed by the last 4 digits must be divisible by 16. The second requirement ensures that the number is divisible by 16.
Nope. 16 is divisible by 1, 2, 4, 8, 16.
Because 8 is 2 cubed, you can test if a number is divisible by 8 by dividing it by 2 three times. If the number you reach is an integer, then the number is divisible by 8. For example, 72/2 = 36/2 = 18/2 = 9. Therefore, 72 is divisible by 8. For very large numbers, if the last three digits are divisible by 8, the number itself is divisible by 8.
Not always for example, 36 is not divisible by 8 but it is divisible by 2 and 4.