If n is the first number, n + n + 1 + n + 2 + n + 3 will be the sum, which is 4n + 6. 4n is always even, and 6 is even. Therefore, the sum of four consecutive numbers is always even.
They will always add up to another even number.
Nop. 2+2+2+4=10
You add 3 to 4 to get 7, therefore the numbers will always be a multiple of 3
There are 7200 such numbers.
The sum of two odd numbers is always even; the sum of three odd numbers is always odd; the sum of four odd numbers is always even; the sum of five odd numbers is always odd; etc
If n is the first number, n + n + 1 + n + 2 + n + 3 will be the sum, which is 4n + 6. 4n is always even, and 6 is even. Therefore, the sum of four consecutive numbers is always even.
Not necessarily. 2 + 6 + 8 + 10 = 26
They will always add up to another even number.
There is no greatest multiple of any number: whatever multiple of 4 you say is the greatest I can always add 4 and get an even greater multiple.
Nop. 2+2+2+4=10
You add 3 to 4 to get 7, therefore the numbers will always be a multiple of 3
No.Any four consecutive numbers must contain two even numbers and two odd numbers.Adding two odd numbers together always gives an even number.Adding two even numbers always gives an even number.To end up with an odd number you need to add and odd number of odd numbers (3 of them, or 5, 7 etc) together.The nearest ways to get four consecutive numbers to come close to 39 are ...* 8+9+10+11 = 38or * 9+10+11+12 = 42
There are 7200 such numbers.
There are four even numbers between one and nine. the four even numbers are 2,4,6 and 8.
Adding 4 odd numbers together will always equal an even number - got ya!
No, the sum of four even numbers is not always a multiple of 4.. For example, 4 + 6 + 10 + 14 = 34 which is not a multiple of 4 If you include an "odd" number of even numbers which are not multiples of 4, then the total will not divide exactly by 4. In the above example 6 = 4 + 2, 10 = 4 + 4 + 2, and 14 = 4 + 4 + 4+ 2, and the total of the odd number of twos will not divide by 4 All multiples of 4 are the product of 2 with another even number: (Let a multiple of 4 be 4k. But 4 = 2 x 2, so 4k = (2 x 2)k = 2 x 2k and 2k is an even number for all k.) Let the four even numbers be 2k, 2m, 2n, 2p for some k, m, n, p. Then their sum is 2k + 2m + 2n + 2p = 2 (k + m + n + p) = 2q where q = k + m + n + p. k, m, n & p can be even or odd. If one, or three, of these is odd, then their sum, q, is odd. To be a multiple of 4 the sum k + m + n + p (= q) must be even. If it is odd, then twice it will not be a multiple of 4. For example, if k = 1, m = 2, n = 3, p = 5, then the four even numbers are 2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 2 x 5 = 10 and their sum is 2 x (1 + 2 + 3 + 5) = 2 x 11 = 22 which is not a multiple of 4.