no
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If R = (xr, yr) and P = (xp, yp) then the midpoint is [(xr + xp)/2, (yr + yp)/2].
four stroke.
(x + 1)10 = 1 + 10x + 45x2 + 120x3 + 210x4 + 252x5 + 210x6 + 120x7 + 45x8 + 10x9 + x10 The coefficient of xr is 10!/[r!*(10-r)!] or 10Cr
as long as its not seroquel xr (youll destroy the extended release part) yes, you should be able to. I of course advice talking to your doctor about doing this first, and using a pill cutter for an accurate cut.
Divide each vector into components, that is, find components in the x, y and z direction that add up to give the vector. This requires some basic trigonometry. Then, add the the components. * * * * * In 2-d the answer is as follows: Suppose the two vectors have magnitude R and are angles A and B to the x-axis. Therefore, the horizontal components of the two vectors are RcosA and RcosB so that the resultant has horizontal component RcosA + RcosB XR = 2R*cos[(A+B)/2]*cos[(A-B)/2] The vertical components of the original two vectors are RsinA and RsinB so that the resultant has horizontal component RsinA + RsinB YR = 2R*sin[(A+B)/2]*cos[(A-B)/2] From these two equations, the magnitude of the resultant is sqrt(XR2 + YR2) = sqrt{4R2*cos2[(A-B)/2]} = 2R*cos[(A-B)/2] and the direction of the resultant is arctan(YR/XR) = arctan{[(A+B)/2]} = (A+B)/2 or equivalent