A*B=B*A is an example of the commutative property of multiplication.
[(aa + bb) + (ab+ba)(aa+bb)*(ab+ba)]*[a + (ab+ba)(aa+bb)*b]
Yes.
Yes, provided it is the ray. If AB is a vector then the answer is no.
yes
A*B=B*A is an example of the commutative property of multiplication.
According to the symmetric property (and common sense) line segmetn AB is congruet to line segment BA since they are the same segment, just with a different name
the basic number properties in math are associative, commutative, and distributive associative: (for addition) a+(b+c)=(a+b)+c (for multiplication) a(bc)=(ab)c or a*(b*c)=(a*b)*c commutative: (for addition) a+b=b+a (for multiplication) a*b=b*a or ab=ba distributive: a(b+c)=ab+ac or a(b+c)=a*b + a*c
Using the communative property of both addition and multiplication, 11+ab could be rewritten as ab+11, 11+ba or ba+11.
ab = 8-cDivide both sides by ba = (8-c)/b
BS
If these are vectors, then ba = - ab
The commutative property states that ab = ba.
A = 1, B = 9
With the information given in the question, we can't find the value of either 'a' or 'b' yet, because there's really only one equation given so far. The statement "ab = ba" is an "identity", not an equation. It's simply a statement of the commutative property of multiplication, and it's true for all values of 'a' and/or 'b'. There's no information in it.
Given that ab = ba and bc = cb We can arrive at abbc = cbba by adding equal quantities to both sides of the equation By the cancellation law you're allowed to drop the bb from both sides of the equation to end up with ac = ca
The GCF is ab