Yes. The proof is easy. Let x be the irrational number and assume there exists some rational number r = a/b where a and b are integers (that's what it means to be rational).
Now suppose x/r is a rational number. Then x/r = (b/a)x = c/d where c and d are some other integers.
Since (b/a)x=c/d, then
x = bd/ac
which means that x itself is rational, but we assumed it was irrational.
The contradiction proves that the assertion is wrong. An irrational divided by a rational must be irrational.
No. sqrt(2)/pi is not rational.
Irrational.
No.A rational times an irrational is never rational. It is always irrational.
Yes. Any irrational number can be divided by itself to produce 1, which is a rational number.
It is always irrational.
No. sqrt(2)/pi is not rational.
Irrational.
When a rational numbers is divided by an irrational number, the answer is irrational for every non-zero rational number.
No.A rational times an irrational is never rational. It is always irrational.
Yes. Any irrational number can be divided by itself to produce 1, which is a rational number.
It is always irrational.
It is always irrational.
It will be irrational.
The product of an irrational number and a rational number, both nonzero, is always irrational
The product of a rational and irrational number can be rational if the rational is 0. Otherwise it is always irrational.
Such a product is always irrational - unless the rational number happens to be zero.
If an irrational number is added to, (or multiplied by) a rational number, the result will always be an irrational number.