No. The average speed is the average of the magnitude of the velocity but not the magnitude of the average of the velocity.
This is because for vectors |A + B| ≤ |A| + |B|.
Suppose you travel 100 metres due East at 10 metres per second and then 100 metres due North also at 10 metres per second. Your speed, throughout, is 10 metres per second and so that is your average speed.
But your average velocity is the total displacement vector divided by the total time. This is
100*sqrt(2) metres due NE/20 sec = 7.07 metres per second due North East.
Its magnitude is 7.07 metres/sec.
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velocity is a vector and speed is scalar. Velocity has magnitude and directions, with magnitude being speed. The magnitude of average velocity and average speed is the same.
Velocity is a vector, and so it has two components -- magnitude (speed) and direction. Speed is a scalar, and it is the magnitude of velocity, a vector.
The definition of speed is the size/magnitude/measure of an object's velocity. Average speed = distance divided by time
No. Speed is the magnitude of velocity and acceleration is the change of velocity in time.
Speed (which is a magnitude), and the direction.Speed (which is a magnitude), and the direction.Speed (which is a magnitude), and the direction.Speed (which is a magnitude), and the direction.