'e' is an imaginary number, multiplied by anything gives an imaginary result
Yes. The number 1 + i is imaginary but not pure imaginary, while 5i is pure imaginary.
It is a pure imaginary number.Since (a+bi)-(a-bi) = 2bi, it is a pure imaginary number (it has no real component).
e is not an imaginary number. e is Euler's constant.Uh...imaginary numbers can equal almost any number in math; it depends upon the application.Imaginary numbers can represent 1 or -1; it depends upon the applicaiton.1e is not prime; it is Euler's constantNothing in the question I posted has an exponent of zero. (You may want to ask a math professor to explain why a number with an exponent of zero is equal to one.)You may want to ask a math professor to explain what an imaginary number means in math.You may want to ask a math professor or someone else to explain what the smalest value is that solves tan ex = 1.e=mc2 is a totally different problem, a totally different value for e. In that case e = energy, m = mass and c = the speed of light. Different application.The number e to the power of zero is not an issue in this problem (it equals 1)An exponent can be a positive or negative number.
No, but √-23 is. An imaginary number is the square root of a negative number.
'e' is an imaginary number, multiplied by anything gives an imaginary result
Yes. The number 1 + i is imaginary but not pure imaginary, while 5i is pure imaginary.
If a number is pure imaginary then it has no real component. If it is a real number, then there is no imaginary component. If it has both real and imaginary components, then it is a complex number.
an imaginary number is imaginary so no (i guess) this answer kind of sucks
-125 is NOT an imaginary number.
That quotient would be an imaginary number. The actual number depends on exactly what imaginary number you divide the 7 by.
It is a pure imaginary number.Since (a+bi)-(a-bi) = 2bi, it is a pure imaginary number (it has no real component).
e is not an imaginary number. e is Euler's constant.Uh...imaginary numbers can equal almost any number in math; it depends upon the application.Imaginary numbers can represent 1 or -1; it depends upon the applicaiton.1e is not prime; it is Euler's constantNothing in the question I posted has an exponent of zero. (You may want to ask a math professor to explain why a number with an exponent of zero is equal to one.)You may want to ask a math professor to explain what an imaginary number means in math.You may want to ask a math professor or someone else to explain what the smalest value is that solves tan ex = 1.e=mc2 is a totally different problem, a totally different value for e. In that case e = energy, m = mass and c = the speed of light. Different application.The number e to the power of zero is not an issue in this problem (it equals 1)An exponent can be a positive or negative number.
No, but √-23 is. An imaginary number is the square root of a negative number.
The answer is relatively simple if you know hyperbolic functions. Suppose x is real so that ix is an imaginary number. Then tanh x = -i*tan(ix) So tan(ix) = (tanh x )/-i = i*tanh x = i * sinh x/csh x = i*(ex - e-x)/(ex + e-x) = i*(1 - e-2x)/(1 + e-2x)
An imaginary number is a number that has the square root of -1 as one of its factors.
???