96 and 69
Sum of digits of 627 = 6+2+7 = 15 15 is exactly divisible by 3. Hence, 627 is divisible by 3. So, it is not a prime number
A number is divisible by 15 if it is divisible by 5, and by 3. For example, 165 is divisible by 15, since it ends in 5, and the sum of its digits is divisible by 3.
All numbers divisible by 5 (of which 15 is a multiple) have a final digit of 0 or 5. All numbers divisible by 3 (of which 15 is a multiple) have the sum of the digits totalling 3 or a multiple of 3. Therefore, a number is divisible by 15 if the sum of its digits total 3 or a multiple of 3 and its final digit is 0 or 5. Example : 32085 ; 3 + 2 + 0 + 8 + 5 = 18 which is divisible by 3. Final digit 5. This number is divisible by 15. (32085 ÷ 15 = 2139) 7420 : 7 + 4 + 2 + 0 = 13. This number is not divisible by 15.
Nope - in order for a number to be divisible by 9, the sum of its digits must also be divisible by 9. In this case, the digits 2+4+2+7=15.
Any number whose sum of its digits are equal to a multiple of 3, is divisible by 3. In this instance, the sum of the digits of the number 34215 is equal to 15, which is divisible by 3, and therefore the number is divisible by 3.
Sum of digits of 627 = 6+2+7 = 15 15 is exactly divisible by 3. Hence, 627 is divisible by 3. So, it is not a prime number
A number is divisible by 15 if it is divisible by 5, and by 3. For example, 165 is divisible by 15, since it ends in 5, and the sum of its digits is divisible by 3.
All numbers divisible by 5 (of which 15 is a multiple) have a final digit of 0 or 5. All numbers divisible by 3 (of which 15 is a multiple) have the sum of the digits totalling 3 or a multiple of 3. Therefore, a number is divisible by 15 if the sum of its digits total 3 or a multiple of 3 and its final digit is 0 or 5. Example : 32085 ; 3 + 2 + 0 + 8 + 5 = 18 which is divisible by 3. Final digit 5. This number is divisible by 15. (32085 ÷ 15 = 2139) 7420 : 7 + 4 + 2 + 0 = 13. This number is not divisible by 15.
Nope - in order for a number to be divisible by 9, the sum of its digits must also be divisible by 9. In this case, the digits 2+4+2+7=15.
American Express is the credit card that has exactly 15 digits in its card number.
To determine if 483 is divisible by 9, we can add the digits of 483 together: 4+8+3 = 15. Since 15 is not divisible by 9 (15 ÷ 9 = 1 with a remainder of 6), we can conclude that 483 is not divisible by 9. In general, a number is divisible by 9 if the sum of its digits is divisible by 9.
Any number whose sum of its digits are equal to a multiple of 3, is divisible by 3. In this instance, the sum of the digits of the number 34215 is equal to 15, which is divisible by 3, and therefore the number is divisible by 3.
A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3
It means make the piece as wide as you need to, but be sure that your total number of stitches is exactly divisible by 15.
13830 = 4610*3 and 15*922
If the digits of a number add up to a multiple of 3, then the number can be divided by 3. For example, the digits of 852 add up to 8 + 5 + 2 = 15. Since 15 is divisible by 3, 852 is divisible by 3.
Yes it is - it's 5088 exactly.