A curved line can pass through (not threw) all four quadrants. The maximim for a straight line is three.
I would say from an educated guess that it is 0. A straight line could avoid all quadrants if it were placed on the origins of the x and y axis.
II and IV
Yes, it is possible.
True. In Euclidean geometry, if there is a line and a point not on that line, there exists exactly one line that can be drawn through the point that is parallel to the given line. This is known as the Parallel Postulate, which states that for a given line and a point not on it, there is one and only one line parallel to the given line that passes through the point.
A curved line can pass through (not threw) all four quadrants. The maximim for a straight line is three.
Quadrants I and III, numbered from I at upper right (+, +) left and moving clockwise. The line passes through the origin (0,0).
Only in a single quadrant? No. A line can be in two, or in three, different quadrants.
It will pass through the first (when x is positive) and third quadrants (when x is negative, y will also be negative).
I,ii
I would say from an educated guess that it is 0. A straight line could avoid all quadrants if it were placed on the origins of the x and y axis.
II and IV
It intercepts the y axis at (0, 5) and it intercepts the x axis at (-2.3, 0) passing through the I, II and III quadrants
Yes, it is possible.
The point (-1,0) lies on the boundary line between Quadrants II and III .
It's a line of infinite extent, and should be drawn in blue or black on the graph, solid, and with the smallest possible thickness. The line is vertical, perpendicular to the x-axis, passing through the point [ x = -2 ], parallel to the y-axis, and traversing the Second and Third Quadrants.
No, that isn't possible.