Yes, it is possible for a line to pass through exactly two quadrants. For instance, a line that has a positive slope can pass through the first and third quadrants if it extends from the second quadrant to the fourth. Similarly, a line with a negative slope can pass through the second and fourth quadrants. In both cases, the line does not intersect the axes in such a way that it enters all four quadrants.
A curved line can pass through (not threw) all four quadrants. The maximim for a straight line is three.
I would say from an educated guess that it is 0. A straight line could avoid all quadrants if it were placed on the origins of the x and y axis.
II and IV
Yes, a line can be in two quadrants if it crosses the axes. For example, a line that extends from the first quadrant to the third quadrant will intersect both the x-axis and y-axis, thus occupying portions of both quadrants. Similarly, lines can exist in any combination of quadrants depending on their slope and position relative to the axes.
Yes, it is possible.
A curved line can pass through (not threw) all four quadrants. The maximim for a straight line is three.
Quadrants I and III, numbered from I at upper right (+, +) left and moving clockwise. The line passes through the origin (0,0).
Only in a single quadrant? No. A line can be in two, or in three, different quadrants.
It will pass through the first (when x is positive) and third quadrants (when x is negative, y will also be negative).
I,ii
I would say from an educated guess that it is 0. A straight line could avoid all quadrants if it were placed on the origins of the x and y axis.
II and IV
It intercepts the y axis at (0, 5) and it intercepts the x axis at (-2.3, 0) passing through the I, II and III quadrants
Yes, it is possible.
The point (-1,0) lies on the boundary line between Quadrants II and III .
It's a line of infinite extent, and should be drawn in blue or black on the graph, solid, and with the smallest possible thickness. The line is vertical, perpendicular to the x-axis, passing through the point [ x = -2 ], parallel to the y-axis, and traversing the Second and Third Quadrants.
No, that isn't possible.