yes. Equilibrium can either be static i.e no movement or dynamic i.e movement is allowed. The main determining factor for equilibrium is that all forces acting at a point or points add up to zero.
It is impossible to tell. You can have two forces that are in equilibrium or three forces and, from outside the system, it may not be possible to tell which.However, on the basis that the unverse is expanding, though not at a constant rate, there must be at least one force that is not balanced.It is impossible to tell. You can have two forces that are in equilibrium or three forces and, from outside the system, it may not be possible to tell which.However, on the basis that the unverse is expanding, though not at a constant rate, there must be at least one force that is not balanced.It is impossible to tell. You can have two forces that are in equilibrium or three forces and, from outside the system, it may not be possible to tell which.However, on the basis that the unverse is expanding, though not at a constant rate, there must be at least one force that is not balanced.It is impossible to tell. You can have two forces that are in equilibrium or three forces and, from outside the system, it may not be possible to tell which.However, on the basis that the unverse is expanding, though not at a constant rate, there must be at least one force that is not balanced.
False
false
False
The result is a direct consequence of the sine rule.
If the ring has shifted horizontally away from the center of the force table and is still in equilibrium, it means that the forces acting on the ring are balanced. This could be due to the forces being applied at an angle, creating a net force that balances out the shift. In such a case, the ring will still remain in equilibrium as long as the net force acting on it is zero.
Yes, a force acting perpendicular to a horizontal force on a body can cancel out the horizontal force if the two forces are equal in magnitude and opposite in direction. This is known as the equilibrium condition, where the net force acting on the body is zero.
A body is in equilibrium when the force on it is zero, thus if a single force is on the body, the force must be zero or the body will not be equilibrium.
A force that causes equilibrium is called an equilibrium force. This force acts in the opposite direction to an applied force to keep an object in a stable position without any net movement.
There has to be no force or energy between two objects to have equilibrium force. #kayleyjonas# age 10
A body is in equilibrium when the force on it is zero, thus if a single force is on the body, the force must be zero or the body will not be equilibrium.
The magnitude of the resultant force in the case of the concurrent forces in equilibrium.
No. For equilibrium, the SUM OF ALL FORCES acting on an object must be zero, and that is not possible with a single (non-zero) force.Note: For equilibrium, the sum of all torques on an object must ALSO be zero.
The force of gravity acts as the restoring force in a pendulum. When the pendulum is displaced from its equilibrium position, gravity acts to restore it back to its original position. This restoring force causes the pendulum to oscillate around the equilibrium point.
The maximum displacement for equilibrium occurs when the restoring force is at its maximum, which is equal to the applied force. This displacement is known as the equilibrium position, where the net force acting on the object is zero.
Rest implies stationary, equilibrium implies a resultant force of zero. Therefore, a body in equilibrium could be moving, for example a sky diver at terminal velocity, where resistive forces are equal to the force of gravity. This means that a body can be in equilibrium and not at rest, but a body at rest MUST be in equilibrium, otherwise it would move. So, to answer the question is: It's impossible.
Equilibrium is not a force, it is a state in which all the forces acting on an object are balanced, resulting in no change in its motion. When an object is in equilibrium, the net force acting on it is zero.