albebra required for this
let a = side 1 and side 3 of a rectangle
let b = side 2 and side 4 of a rectangle
then the perimeter = a + b + a + b = 2a + 2b+ 28
and the area = a x b = 18
taking 2a + 2b = 28 and making a the subject of the formula you get a = 28-b
taking a= 28-b into the axb = 18 formula gives
b(28-b)=18
so b2-28b+18 = 0
by quadratic formula . i will say b = 14 +/- the root of 178
which you can work out. sorry i have run out of time
b
That would be very difficult to explain, because it's not true. Consider this rectangle: Length = 7.64575 units Width = 2.35425 units Perimeter = 20 units Area = 18 square units =================================== Precise dimensions are: 5 + sqrt(7) 5 - sqrt(7)
17. A 4x4 rectangle has a perimeter of 16 units and an area of 16 square units. A 3x6 rectangle has a perimeter of 18 units and an area of 18 square units. The number 17 is halfway between 16 and 18.
Perimeter: 2(4+5) = 18 units Area: 4*5 = 20 square units
The answer will depend on what those numbers represent and their units. It is possible that the question gives 18 and 5 units as the length and width of a rectangle and requires you to find the area and perimeter. Or It is possible that the question has given 18 in some units and 5 in some other units and requires you to determine which one could be the area and which the perimeter.
Assuming that the fact that it is a rectangle means that it cannot be a square, then it can have any value in the interval (0, 20.25) square units. This depends on whether the rectangle is a long thin shape or a near-square.
The square root of 324 is 18 and 4*18 = 72 units of measurement which is the perimeter of the square.
That would be very difficult to explain, because it's not true. Consider this rectangle: Length = 7.64575 units Width = 2.35425 units Perimeter = 20 units Area = 18 square units =================================== Precise dimensions are: 5 + sqrt(7) 5 - sqrt(7)
17. A 4x4 rectangle has a perimeter of 16 units and an area of 16 square units. A 3x6 rectangle has a perimeter of 18 units and an area of 18 square units. The number 17 is halfway between 16 and 18.
Perimeter: 2(4+5) = 18 units Area: 4*5 = 20 square units
The answer will depend on what those numbers represent and their units. It is possible that the question gives 18 and 5 units as the length and width of a rectangle and requires you to find the area and perimeter. Or It is possible that the question has given 18 in some units and 5 in some other units and requires you to determine which one could be the area and which the perimeter.
Assuming that the fact that it is a rectangle means that it cannot be a square, then it can have any value in the interval (0, 20.25) square units. This depends on whether the rectangle is a long thin shape or a near-square.
72 / 4 = 18 per side18 * 18 = 324 units^2
Length + width = ½ of perimeter ie 9 units. Area could be anything from 8 square units (8 x 1) to 20 square units (5 x 4), assuming there are no fractional measurements and that rectangle is not a square.
Make a 3x3 box and a 2x6 box, and join them connecting 2 of the lines.
Given a perimeter of 18 units, the resulting altitude is 5.2 (5.19615) units.
The perimeter of a square with sides of 4.5m is 4*4.5m = 18 metres.
Area of square: 324 square inches Perimeter of square: 72 inches