Yes.
Any even number can be expressed as 2x (where x is an integer).
(2x)2 = 4x2. We don't know exactly what x2 is, and we don't need to know, because we know that the square of any integer is also an integer, and any integer multiplied by 4 is an even number.
A direct proof in geometry is a proof where you begin with a true hypothesis and prove that a conclusion is true.
Most high school algebra books show a proof (by contradiction) that the square root of 2 is irrational. The same proof can easily be adapted to the square root of any positive integer, that is not a perfect square. You can find the proof (for the square root of 2) on the Wikipedia article on "irrational number", near the beginning of the page (under "History").
theorem
If I tell you that the square root of 2 (for example) is such-and-such, you can verify this by multiplying the number by itself, and seeing whether the result is close to 2.
Search for the proof for the irrationality of the square root of 2. The same reasoning applies to any positive integer that is not a perfect square. In summary, the square root of any positive integer is either a whole number, or - as in this case - it is irrational.
A direct proof of the infinity of primes would require what is essentially a formula to calculate the Nth prime number; such a formula isn't even guaranteed to exist. It's possible to formulate a proof of the infinity of primes that would be, in a sense, direct. A direct proof that the square root of 2 is irrational is impossible, because the irrational numbers aren't defined in any direct way - just as the real numbers which aren't rational. So to prove that the square root of 2 is irrational, we have to prove that it's not rational, which requires indirect techniques.
A direct proof in geometry is a proof where you begin with a true hypothesis and prove that a conclusion is true.
Yes. The square root of a positive integer can ONLY be either:* An integer (in this case, it isn't), OR * An irrational number. The proof is basically the same as the proof used in high school algebra, to prove that the square root of 2 is irrational.
The square root of a positive integer can ONLY be:* Either an integer, * Or an irrational number. (The proof of this is basically the same as the proof, in high school algebra books, that the square root of 2 is irrational.) Since in this case 32 is not the square of an integer, it therefore follows that its square root is an irrational number.
There is no direct proof and dates are estimates.
Most high school algebra books show a proof (by contradiction) that the square root of 2 is irrational. The same proof can easily be adapted to the square root of any positive integer, that is not a perfect square. You can find the proof (for the square root of 2) on the Wikipedia article on "irrational number", near the beginning of the page (under "History").
No, the square root of 3 is not rational.No. The square root of 3 is irrational.More generally: if p is a prime number then the square root of p is irrational and the proof of this fact mimics the famous proof of irrationality of the square root of 2.No - the square root of 3 is not rational, but the proof is too involved to post here.
proof number
theorem
If I tell you that the square root of 2 (for example) is such-and-such, you can verify this by multiplying the number by itself, and seeing whether the result is close to 2.
There is a proof that there is no such formula for generating all the prime numbers. Best, TSA
Search for the proof for the irrationality of the square root of 2. The same reasoning applies to any positive integer that is not a perfect square. In summary, the square root of any positive integer is either a whole number, or - as in this case - it is irrational.