No, it is false -9 is less than 4 .
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No not always true. Say you have a mixed number of 4 and 9/10 tines a fraction 9/10 you have 49/10 x 9/10 = 441/100 = 4.41 which is greater than 4
The answer is greater than, because 7 divided by 9 is .777777, and 2 divided by 4 is .5 .777 is greater than .5, and so 7/9ths is the greater of the two equations
We can convert both ninths and sevenths into a common fraction, by multiplying nine by seven, to get 63. So, 4/9 = 28/63 and 3/7 = 27/63. You can then easily see that 28/63 is exactly 1/63 larger than 27/63. So it is true, 4/9 is indeed greater than 3/7. Not much greater, but slightly greater.
To determine if segments with lengths 9, 4, and 11 can form a triangle, we can use the triangle inequality theorem. This states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 9 + 4 = 13, which is greater than 11; 9 + 11 = 20, which is greater than 4; and 4 + 11 = 15, which is greater than 9. Since all conditions are satisfied, the segments can indeed form a triangle.
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The symbol is < or > for example 10 > 9 this means 10 is greater than 9. But if you put 10 < 9 this would be incorrect because it indicates 9 is greater than 10 which is not true.
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3/4 = 0.75 9/10 = 0.9 9/10 is 20% greater than 3/4 .
Yes it is. Converted into decimals, 7/9 = .77... and 3/4 = .75 .77 is greater than .75 That means 7/9 is greater than 3/4
No not always true. Say you have a mixed number of 4 and 9/10 tines a fraction 9/10 you have 49/10 x 9/10 = 441/100 = 4.41 which is greater than 4
4
-5/9 is greater.
42/9 is much greater. 42/9 is the same as 4 and 7/9 (since 9 goes into 42 4 times with 7 left over). Since 5/9 is less than 1, clearly 42/9 is much greater. 7/9 alone would still be greater than 5/9. But since it's not just 7/9, but 4 and 7/9, it is obviously greater than 5/9.
If you mean 9/12 then it is greater than 1/4
The answer is greater than, because 7 divided by 9 is .777777, and 2 divided by 4 is .5 .777 is greater than .5, and so 7/9ths is the greater of the two equations