1 times 7 is 7 ....... 2 times 7 is 14 ....... ....... 3 times 7 is 21 ....... ....... ....... 4 times 7 is 28 ....... ....... ....... ....... 5 times 7 is 35 ....... ....... ....... ....... ....... 6 times 7 is 42 ....... ....... ....... ....... ....... ....... 7 times 7 is 49 ....... ....... ....... ....... ....... ....... ....... 8 times 7 is 56 ....... ....... ....... ....... ....... ....... ....... ....... 9 times 7 is 63 ....... ....... ....... ....... ....... ....... ....... ....... ....... 10 times 7 is 70 ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... 11 times 7 is 77 ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... 12 times 7 is 84 ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... .......
7 times 7 times 2 is equal to 98.
5 + 11 11 + 5 7 + 9 9 + 7 So 4 ways if you are allowed to throw each die only once. But the question did not state that assumption; so the additional ways are: Throw die #1 16 times and get 1 each time. Throw die #2 16 times and get 1 each time. Throw die # 1 13 times and get 1 13 times and 3 once. Throw die # 2 13 times and get 1 13 times and 3 once. Throw die #1 13 times and get 1 each time, then throw die # 2 once and get 3. Throw die #1 12 times and get 1 each time, then throw die #2 once and get 3, then throw die #1 again and get another 1. You get the idea, figure out the rest yourself.
If a DIE (not dice) is rolled 90 times, the expected value of the sum of the first and second rolls is 7 if you assume that the die is fair. It does not matter how many times you roll the die, as long as it is at least 2.
A standard die has no memory and so the probability of rolling an even number is always a half. If you did not know that the die was standard and were using the fact that 7 out of 12 rolls were even as an empirical estimate for a loaded die then the answer is 7/12.
7x8=56 is true
You can't...unless it is not a traditional die
Andrea True died on November 7, 2011, in Kingston, New York, USA of heart failure.
It is true it is true that i work at 7/11, but just like my store your moms legs are open 24/7 :) nd u kno it
No. that's just a fictional part of the movie.
117,649
The probability of rolling doubles on a fair six-sided die is 1/6. To roll doubles 7 times in a row, you would need to multiply this probability by itself 7 times, resulting in (1/6)^7. This equals approximately 1 in 78,364,164,096, which means the chances of rolling doubles 7 times in a row are extremely low.
1 times 7 is 7 ....... 2 times 7 is 14 ....... ....... 3 times 7 is 21 ....... ....... ....... 4 times 7 is 28 ....... ....... ....... ....... 5 times 7 is 35 ....... ....... ....... ....... ....... 6 times 7 is 42 ....... ....... ....... ....... ....... ....... 7 times 7 is 49 ....... ....... ....... ....... ....... ....... ....... 8 times 7 is 56 ....... ....... ....... ....... ....... ....... ....... ....... 9 times 7 is 63 ....... ....... ....... ....... ....... ....... ....... ....... ....... 10 times 7 is 70 ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... 11 times 7 is 77 ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... 12 times 7 is 84 ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... .......
7 to the power of 5 is 16,807.
7 times 7 times 2 is equal to 98.
7 x 7 x 7 x 7 = 2401
5 + 11 11 + 5 7 + 9 9 + 7 So 4 ways if you are allowed to throw each die only once. But the question did not state that assumption; so the additional ways are: Throw die #1 16 times and get 1 each time. Throw die #2 16 times and get 1 each time. Throw die # 1 13 times and get 1 13 times and 3 once. Throw die # 2 13 times and get 1 13 times and 3 once. Throw die #1 13 times and get 1 each time, then throw die # 2 once and get 3. Throw die #1 12 times and get 1 each time, then throw die #2 once and get 3, then throw die #1 again and get another 1. You get the idea, figure out the rest yourself.