no its not true if you sneez 7 times you will die that is a myth
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1 times 7 is 7 ....... 2 times 7 is 14 ....... ....... 3 times 7 is 21 ....... ....... ....... 4 times 7 is 28 ....... ....... ....... ....... 5 times 7 is 35 ....... ....... ....... ....... ....... 6 times 7 is 42 ....... ....... ....... ....... ....... ....... 7 times 7 is 49 ....... ....... ....... ....... ....... ....... ....... 8 times 7 is 56 ....... ....... ....... ....... ....... ....... ....... ....... 9 times 7 is 63 ....... ....... ....... ....... ....... ....... ....... ....... ....... 10 times 7 is 70 ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... 11 times 7 is 77 ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... 12 times 7 is 84 ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... ....... .......
7 times 7 times 2 is equal to 98.
If a DIE (not dice) is rolled 90 times, the expected value of the sum of the first and second rolls is 7 if you assume that the die is fair. It does not matter how many times you roll the die, as long as it is at least 2.
5 + 11 11 + 5 7 + 9 9 + 7 So 4 ways if you are allowed to throw each die only once. But the question did not state that assumption; so the additional ways are: Throw die #1 16 times and get 1 each time. Throw die #2 16 times and get 1 each time. Throw die # 1 13 times and get 1 13 times and 3 once. Throw die # 2 13 times and get 1 13 times and 3 once. Throw die #1 13 times and get 1 each time, then throw die # 2 once and get 3. Throw die #1 12 times and get 1 each time, then throw die #2 once and get 3, then throw die #1 again and get another 1. You get the idea, figure out the rest yourself.
It is: 7 times 7 = 49