No, -3 is greater than -6.
-6 is greater than -17. Consider temperatures: a temperature of 6°C is warmer than 3°C and would be considered greater (6 > 3); a temperature of -6°C is warmer than -17°C, and so -6 > -17.
To compare (-\frac{7}{3}) and (-\sqrt{6}), we can approximate their values. (-\frac{7}{3} \approx -2.33) and (-\sqrt{6} \approx -2.45). Since (-2.33) is greater than (-2.45), we conclude that (-\frac{7}{3}) is greater than (-\sqrt{6}).
Any negative integer less than -3 meets the criteria of having an absolute value greater than 3. For example, -4, -5, and -6 are all valid answers. The absolute value of these integers (4, 5, and 6, respectively) is indeed greater than 3.
-1 -2 -3 -4 -5 -6 and -7 are all greater than -8
Yes
No because -6 is less than 3
-6 is greater than -17. Consider temperatures: a temperature of 6°C is warmer than 3°C and would be considered greater (6 > 3); a temperature of -6°C is warmer than -17°C, and so -6 > -17.
The negative integers greater than -6 are: -5, -4, -3, -2, -1.
No because -5 is greater than -6
-6 is greater than -7
greater than.
As 6 is a positive integer, no negative integer is greater than it.
-1 -2 -3 -4 -5 -6 and -7 are all greater than -8
yes
Yes
less than
If you consider only the magnitude of the two numbers (disregarding the signs) then 6 is greater than 3. But when we have signed numbers, we have to imagine the number line. On the negative side of zero, a negative number closer to zero is considered greater than a negative number that is farther from zero. Similarly on the positive side of zero, a positive number closer to zero is considered smaller than a positive number that is farther from zero. I hope that explains it. -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6