No. The range of the exponential (antilog) function is the positive reals (unless you are dealing with the complex field).
If it is log to the base 10, use the calculator to find 10 to that power. If it is log to the base e, use the calculator to find e to that power. Both the above are standard functions on all scientific calculators and are easy to work out on spreadsheets. Alternatively, you can find the antilog of the absolute value and then find the reciprocal. Thus antilog(-3.5) = 1/antilog(3.5) etc.
An absolute value can never be a negative. An absolute value is just the distance the # is from the zero...so again for it to be negative thats not possible
Positive X or Negative X
Subtract the log of the divisor from the log of the dividend and then us the antilog table to find the value of the quotient.When using log tables:It is easiest to use logs to base 10;write the numbers in scientific notation, rounding to significant figures equal to the number of figures of the table;look up the mantissa (the bit before the × 10ⁿ) in the log table to get a value between 0 and 1;consider the exponent (the power of 10) as a number to be added to this log value;do the subtraction in two separate parts: subtract the whole numbers and subtract the fractional part (after the decimal point);if the fractional part is negative, add 1 to it to make it positive and subtract 1 from the whole number;look up the fractional part in the antilog table;multiply this value by 10 to the power of the whole number.Instead of rounding to the figures of the table, you can interpolate between the values in the table, but it is likely to not make much difference to the final value, which is only accurate to a maximum of the figures of the table.When adding the exponent to the looked up log value, if it is negative, write is as the absolute value with a bar over it. This is not a strictly correct use of the decimal point - it is really writing something like -1 + 0.345 in a compact form; the point is that the part after the decimal point is always positive whereas the whole number part is the part which may be negative.If you do not have antilog tables, you can find the antilog by finding the log value inside the table and finding the value in the headings.eg in my 3 figure tables, the log of 3.45 is looked up by finding where row 3.4 intercepts column 5 giving a value of 538 which is 0.538.To find the antilog of 0.307 I find 307 in row 2.0 under column 3 meaning the antilog of 0.307 is 2.03If the exact value does not appear in the table, you can interpolate between values to get the closest approximation. eg the antilog of 0.308: 307 → 2.03, 310 → 2.04; 308 is closest to 307, so the antilog to 3 figures would be 2.03Using 3 figure logs to base 10:3533 ÷ 9043 = (3.533 × 10³) ÷ (9.043 × 10³)= 10^(lg(3.533 × 10³) - lg(9.043 × 10³))≈ 10^(lg(3.53 × 10³) - lg(9.04 × 10³))≈ 10^((3 + 0.548) - (3 + 0.956))= 10^(0 - 0.408)= 10^((0 - 1) + (1 - 0.408))= 10^(-1 + 0.592)≈ 3.91 × 10⁻¹= 0.391(Using a calculator I get 3533 ÷ 9043 = 0.39068893..... which to 3 sig fig is 0.391 as found using the log table.)-------------------------------------------------A slide rule is an analogue log table.
4. i is just the imaginarY number used in an equatiOn, where there is a negative root (not possible to have a negative root) All yoU do is multiply the negative Root with a negative one, and you'll See your answer. absoluTe valUe turns any negative number into a Positive, even an Imaginary number. Do this and you'll be fine with your trigonometry!
Value of AntiLog (6) is 1,000,000.00
If it is log to the base 10, use the calculator to find 10 to that power. If it is log to the base e, use the calculator to find e to that power. Both the above are standard functions on all scientific calculators and are easy to work out on spreadsheets. Alternatively, you can find the antilog of the absolute value and then find the reciprocal. Thus antilog(-3.5) = 1/antilog(3.5) etc.
The value of antilog(1.0913) depends on the base to which the logarithm was taken. Antilog(1.0913) = Base1.0913. The two most common bases are e = 2.71828 (approx) and 10. If the base was e, then antilog(1.0913) = e1.0913 = 2.978 If the base was 10, then antilog(1.0913)= 101.0913 = 12.340
An absolute value can never be a negative. An absolute value is just the distance the # is from the zero...so again for it to be negative thats not possible
no.
antilog(-2.6674) = 10-2.6674 = 0.002151 (to 4 dp). Normally, the base for logs should be specified. If not, it is often assumed to be 10. The assumption may be justified on the grounds that the main alternative base is e, but in that case "ln" and "exp" are usually used instead of log and antilog..
Positive X or Negative X
-2, as negative value is not possible.
positive 6 and negative 6. - 6 + 6
No, in physics, speed and displacement are scalar quantities that represent magnitudes and cannot be negative. However, the direction of motion can be indicated by assigning a negative or positive sign to the speed or displacement value.
The absolute value depends on it's "distance" from zero. So if it's to the right (positive) by 5 units, or to the left (negative) by five units, then it's absolute value is 5
No. You can't have less than none of any chemical.