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yes, it is both symmetric as well as skew symmetric

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Q: Is null square matrix a skew symmetric?

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In linear algebra, a skew-symmetric matrix is a square matrix .....'A'

I could be wrong but I do not believe that it is possible other than for the null matrix.

My knowledge limits to square matrices. The answer is yes, because 0 = -0

In a skew symmetric matrix of nxn we have n(n-1)/2 arbitrary elements. Number of arbitrary element is equal to the dimension. For proof, use the standard basis.Thus, the answer is 3x2/2=3 .

int sym_test(const **a,int n){ int i,j,sym; i=1;j=0;sym=1; while(sym && i<n){ if ( a[i][j] != -[j][i] ) sym=0; else if (j<i-1) ++j; else ++i,y=0; } return sym; }

Related questions

A skew symmetric matrix is a square matrix which satisfy, Aij=-Aji or A=-At

Let A be a matrix which is both symmetric and skew symmetric. so AT=A and AT= -A so A =- A that implies 2A =zero matrix that implies A is a zero matrix

In linear algebra, a skew-symmetric matrix is a square matrix .....'A'

I could be wrong but I do not believe that it is possible other than for the null matrix.

My knowledge limits to square matrices. The answer is yes, because 0 = -0

In a skew symmetric matrix of nxn we have n(n-1)/2 arbitrary elements. Number of arbitrary element is equal to the dimension. For proof, use the standard basis.Thus, the answer is 3x2/2=3 .

yes

#include<iostream.h>

They can be either. If they are roots of a real polynomial then purely imaginary would be symmetric and only real roots can be skew symmetric.

Skew-Hermitian matrix defined:If the conjugate transpose, A†, of a square matrix, A, is equal to its negative, -A, then A is a skew-Hermitian matrix.Notes:1. The main diagonal elements of a skew-Hermitian matrix must be purely imaginary, including zero.2. The cross elements of a skew-Hermitian matrix are complex numbers having equal imaginary part values, and equal-in-magnitude-but-opposite-in-sign real parts.

The skew binomial distribution arises when the probability of a particular event is not a half.

No, there cannot be any.

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