It depends what 6(p - 4) - 30p is supposed to equal. Substituting p = -1, gives: 6((-1) - 4) - 30(-1) = 6×-5 - 30×-1 = -30 + 30 = 0 Only if 6(p - 4) - 30p = 0 is p = -1 a solution. Otherwise it is not a solution.
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
Yes and sometimes it can have more than one solution.
Without an equality sign it cannot be classed as an equation therefore it follows that there is no solution.
There is no such pair. The solution to equation 1 and equation 2 is x = 1, y = 1. The solution to equation 2 and equation 3 is x = 1, y = 1. And the solution to equation 1 and equation 3 is any point on the line 3x + 2y = 5 - an infinite number of solutions. The fact that the determinant for equations 1 and 3 is zero (or that they are not independent) does not mean that there is no solution. It means that there is no UNIQUE solution. In this particular case, the two equations are equivalent and so have an infinite number of solutions.
It depends what 6(p - 4) - 30p is supposed to equal. Substituting p = -1, gives: 6((-1) - 4) - 30(-1) = 6×-5 - 30×-1 = -30 + 30 = 0 Only if 6(p - 4) - 30p = 0 is p = -1 a solution. Otherwise it is not a solution.
An equation that has no solution is called an equation that has no solution.
It is 1/30.
There are 3 30p's in £1. But you still have 10p left over needed to make the pound.
1+1=2
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
Yes and sometimes it can have more than one solution.
Without an equality sign it cannot be classed as an equation therefore it follows that there is no solution.
0
Without any equality and not knowing the plus or minus values of 1 and 45 it is not an equation so therefore it has no solution.
To find the fraction of 30p in 5p, we need to divide 30 by 5. This gives us 6. So, the fraction is 6/1 or simply 6. This means that 30p is 6 times greater than 5p.
It is a linear equation in one variable r. The solution to the equation is r = 1.