No because the square root of 2 is an irrational number that can't be expressed as a fraction.
No.
No, the square root of 21 is not a natural number. Natural numbers are positive integers (1, 2, 3, ...), and the square root of 21 is approximately 4.58, which is not an integer. Therefore, it does not qualify as a natural number.
Square root of 2; square root of any natural number that is not a perfect square; the number pi; the number e.
No, the square root of 5 is not a natural number. Natural numbers are the set of positive integers (1, 2, 3, ...), and the square root of 5 is an irrational number, approximately 2.236, which cannot be expressed as a simple fraction or a whole number.
Yes, it's 2
No.
No, the square root of 21 is not a natural number. Natural numbers are positive integers (1, 2, 3, ...), and the square root of 21 is approximately 4.58, which is not an integer. Therefore, it does not qualify as a natural number.
Square root of 2; square root of any natural number that is not a perfect square; the number pi; the number e.
No, the square root of 5 is not a natural number. Natural numbers are the set of positive integers (1, 2, 3, ...), and the square root of 5 is an irrational number, approximately 2.236, which cannot be expressed as a simple fraction or a whole number.
Yes, it's 2
The same reasoning you may have seen in high school to prove that the square root of 2 is not rational can be applied to the square root of any natural number that is not a perfect square.
No. For two reasons: 1) Negative numbers are not natural numbers 2) All natural numbers are rational numbers but the square root of 6 is an irrational number and thus cannot be a natural number.
No because it is an irrational number that can't be expressed as a fraction
They are natural numbers, whole numbers, and integers. 2 is the square root of 4 and 4 is the square of 2.
Yes, the square root of 2 is an irrational number.
.5
The square root of 2 is 1.141..... is an irrational number