It is an Arithmetic Progression with a constant difference of 11 and first term 15.
63
17
15
11, -10, 9
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
Which of the following equations could be used to solve for the tenth term of the following sequence?15, 13, 11, 9, ...
U1 = 27 U{n+1} = U{n} - 3
17?
15
A common difference is a mathematical concept that appears in arithmetic sequences. An arithmetic sequence is a sequence of numbers, U(1), U(2), ... generated by the following rule: U(1) = a U(2) = U(1) + d U(3) = U(2) + d and, in general, U(n) = U(n-1) + d that is, you have a starting number a and, after that, each term in the sequence is found by adding a fixed number, d, to the previous term in the sequence. An equivalent formulation is U(n) = a + (n-1)*d The difference between any two consecutive terms is d and this is the common difference. For example, in the sequence 3, 7, 11, 15, 19, .... the common difference is 4. This is because 7-3 = 4 11-7 = 4 15-11 = 4 and so on.
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
44. You're adding 11 then 9 each time !
u15 = u7 + (15-7)*d = 2.33 + 8*(-0.67) = -3.03
That is called an arithmetic sequence. For example: 8, 15, 22, 29, 36, 43, 50, 57, etc.
A number sequence is not a question. So there can be no "answer".
20