yes it is
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
The sequence 3, 7, 11, 15 is an arithmetic sequence where each term increases by 4. The recursive rule can be expressed as ( a_n = a_{n-1} + 4 ) with ( a_1 = 3 ). The explicit rule for the nth term is ( a_n = 3 + 4(n - 1) ) or simplified, ( a_n = 4n - 1 ).
The sequence 7, 9, 11, 13, 15 is an arithmetic sequence where the first term (a) is 7 and the common difference (d) is 2. The nth term can be calculated using the formula: ( a_n = a + (n-1) \cdot d ). Thus, the nth term is given by ( a_n = 7 + (n-1) \cdot 2 ), which simplifies to ( a_n = 2n + 5 ).
The given linear sequence increases by 3 each time. To find the 15th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 = 5 ) and ( d = 3 ). Plugging in the values, ( a_{15} = 5 + (15-1) \times 3 = 5 + 42 = 47 ). Thus, the 15th term is 47.
63
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
Which of the following equations could be used to solve for the tenth term of the following sequence?15, 13, 11, 9, ...
U1 = 27 U{n+1} = U{n} - 3
17?
15
A common difference is a mathematical concept that appears in arithmetic sequences. An arithmetic sequence is a sequence of numbers, U(1), U(2), ... generated by the following rule: U(1) = a U(2) = U(1) + d U(3) = U(2) + d and, in general, U(n) = U(n-1) + d that is, you have a starting number a and, after that, each term in the sequence is found by adding a fixed number, d, to the previous term in the sequence. An equivalent formulation is U(n) = a + (n-1)*d The difference between any two consecutive terms is d and this is the common difference. For example, in the sequence 3, 7, 11, 15, 19, .... the common difference is 4. This is because 7-3 = 4 11-7 = 4 15-11 = 4 and so on.
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
The sequence 3, 7, 11, 15 is an arithmetic sequence where each term increases by 4. The recursive rule can be expressed as ( a_n = a_{n-1} + 4 ) with ( a_1 = 3 ). The explicit rule for the nth term is ( a_n = 3 + 4(n - 1) ) or simplified, ( a_n = 4n - 1 ).
44. You're adding 11 then 9 each time !
u15 = u7 + (15-7)*d = 2.33 + 8*(-0.67) = -3.03
That is called an arithmetic sequence. For example: 8, 15, 22, 29, 36, 43, 50, 57, etc.
A number sequence is not a question. So there can be no "answer".