No, it is not.
Yes but the parallel bases are of different lengths
No, it is not.
The Trapezoid midsegment conjecture- the midsegment of a trapezoid is parallel to the bases and is equal to the length to the average of the lengths of the bases. This is Some what Algebra....... what you do is take your length 90 and midsegment 85 into a prob like this (90+X)/2=85 times by two on both sides to cancel out the two. after that you end up with 90+X=85 next you have to "isolate" the X by subtracting 90 from both sides you would get 90+X=85 -90 -90 to get X= -5 the other side would be -5 so it doesnt work to check it plug the number back into the equation (90+-5)/2=85
It will be 19 units.
False.
It is the average of the bases.
Yes
It is 20 units.
A trapezoid midsegment is parallel to the set of parallel lines in a trapezoid and is equal to the average of the lengths of the bases
It is (7 + 15)/2 = 11 units of length.
Yes. The midsection is equal to the average of the two bases.
Yes but the parallel bases are of different lengths
No, it is not.
The Trapezoid midsegment conjecture- the midsegment of a trapezoid is parallel to the bases and is equal to the length to the average of the lengths of the bases. This is Some what Algebra....... what you do is take your length 90 and midsegment 85 into a prob like this (90+X)/2=85 times by two on both sides to cancel out the two. after that you end up with 90+X=85 next you have to "isolate" the X by subtracting 90 from both sides you would get 90+X=85 -90 -90 to get X= -5 the other side would be -5 so it doesnt work to check it plug the number back into the equation (90+-5)/2=85
28.5
28.5
25.5 units