no
Actually, yes. The four sides can be labeled A, B, C, D. Doubling each side gives 2A, 2B, 2C, and 2D. Factoring out the two gives the expression 2*(A+B+C+D). We recognize (A+B+C+D) as the perimeter of the square. 2*(the perimeter of the square) is twice the perimeter of the square.
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if it is a 2 inch square and the side lengths are doubled the side lengths would be 4. therefore 4+4+4+4=16 so the perimeter is 16inches squared.
If you double the dimensions, then the perimeter is doubled. However, the area is quadrupled. For example, let's say that a side of a square is x units. The perimeter would be 4x, and the area x2. Now, let's double the dimension into 2x. Now, the perimeter is 8x, and the area is 4x2. As you can see, the perimeter is doubled and the area is quadrupled.
The perimeter is the sum of the sides. So if a square has a side of length 1, its perimeter is 1+1+1=1 = 4 If a square has a side doubled to length 2, its perimeter is 2+2+2+2 = 8, or double what it was before. Mathematically, if each side is length x it perimeter is x + x + x = X = 4x If each side is length 2x, its perimeter is 2x +2x+2x+2x = 8x
Each side of the square is a quarter of the square's perimeter.
The approximate length of each side of a square is one-fourth of the entire perimeter. Each side of a square is always 1/4 of the perimeter. However, the exact approximation may vary because the perimeter of the square is not provided nor can be derived.