Not always.
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if divide the prime numbers by the compositenumber it will give you a greater number that is either a prime number or composite.
Not if either of the numbers is between 0 and 1. 5*0.5 = 2.5 is not greater than 5 0.3*0.4 = 0.12 is smaller than both multiplicands.
"Either" is used for two. I'll assume that you mean "larger than ANY of them". The following applies to ANY real numbers.For TWO numbers, the product is larger than either of them if both numbers are greater than one. For THREE numbers, the product is larger than any of them if the two numbers OTHER than the largest number have a product greater than one. For example: 0.5, 3, 5 The largest number here is 5; the product of the OTHER two is 0.5 x 3 = 1.5. Or here is an example with integers: -5, -3, 10 The product of the "other two" numbers is 15, which is larger than one - so the product of all three is larger than the largest number (and therefore, larger than ANY of them). Another example: -5, 1, 10 The product of the two numbers OTHER than the largest is -5 x 1 = -5; since this is NOT greater than 1, the product of all three is NOT greater than any of the numbers. This reasoning can be extended to four or more numbers. For 4 numbers: If the product of all three numbers OTHER than the largest one is GREATER than one, then the product of ALL FOUR numbers is greater than ANY of them.
Yes. Natural numbers are counting numbers, equal to or greater than 0. The only ways a product can be less than its multiplicands is when multiplying fractions by fractions or multiplying a positive number by a negative number.
Positive numbers are greater than negative numbers. Decimals can be either positive or negative.