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What is the solution to 5m equals 40?
5m = 40m = 40/5m = 8
What is the area of a triangle that has a base of 5m and a height of 8m?
20 sq. m
What is the area of a triangle that has a base of 5 m and a height of 8 m?
5m*8m = 40m/2=20 20 is your answer
-7m-3m plus 5m?
-7m - 3m + 5m = -5m
What fraction of 5m is 25cms?
25 cm is 1/20th of 5 m.
What is the solution to 5m equals 40?
5m = 40m = 40/5m = 8
How do you make 100mm from 5M solution?
To make 100mL of 5M solution, you could dilute 10mL of the 5M solution with 90mL of solvent (usually water) to achieve the desired volume. This would retain the 5M concentration while reducing the volume to 100mL.
What is the Perimeter of a room 5m x 4m equals?
20
PH of a 7.2x10-5M solution?
The pH is 4,14.
How can you make solution of 2M of 800 ml from 5M solution?
In order to have a 2M solution is means that you have 2 moles for every 1 liter. Because you only want to make 800mL of this solution you only need (0.8*2) moles of or 1.6 moles of the compound in your solution. This 1.6 moles is coming from your 5M solution. So how much 5M do you need to take out to have 1.6 moles. A 5 molar solution has 5 moles for every liter, since you only need 1.6 moles of it that you need(1.6/5) liters of the solution or 0.32 liters (320 mL). Calculations done. So your going to take 320 mL of the 5M solution and put it into an 800mL volumetric flask and add water up to the line, or to be more exact, add exactly 460 mL of water in order to dilute the solution from 5M to 800mL of 2M solution.
What is 5m equals 20?
m = 4
How would you prepare 30mL of a 5M NaCl solution from a 2M NaCl stock solution?
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
What volume of a 3m koh solution can be prepared by diluting 0.5 l of a 5m koh solution?
To dilute the 5M KOH solution to 3M, we can use the formula: M1V1 = M2V2, where M1 = initial molarity, V1 = initial volume, M2 = final molarity, and V2 = final volume. Plugging in the values, we get: (5M)(0.5L) = (3M)(V2). Solving for V2 gives V2 = 0.5 * 5 / 3 = 0.833 L. So, 0.833 liters of 3M KOH solution can be prepared by diluting 0.5L of 5M KOH solution.
What is 8m negative 4m negative 6 negative 3 positive 5m equals?
8 - 4 - 6 - 3 + 5 = 0
What is 25 percent of 20m?
25% of 20m= 25% * 20= 0.25 * 20= 5m
How many grams of KMnO4 should be used to prepare 2L of a 5M solution?
To prepare 2L of a 5M solution, you should put in 4.6575grams of KMnO4. It is important to make sure that you add them in that order. K should be added first, then Mn.
How do you calculate the concentration of two mixed solutions?
calculate final molarity of the solution if 11ml of 5m solution is made up to 20ml
