Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
Its the square root of 2 times x Ambiguous. More clear is x times square root of 2
2x square root 6x y squared
sqrt(8xy2) * sqrt(20y) = 2y*sqrt(2x)*sqrt(20y) = 4y*sqrt(x)*sqrt(10y) = 4y*sqrt(10xy)
In real numbers there is no square root of -4x2 However, when using complex numbers where √-1 = i, then: √-4x2 = 2xi If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving: y2 - 4x2 = (y + 2x)(y - 2x)
the square root of 164= 2x the square root of 41
the square root of 164= 2x the square root of 41
7
Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
Its the square root of 2 times x Ambiguous. More clear is x times square root of 2
2x square root 6x y squared
sqrt(8xy2) * sqrt(20y) = 2y*sqrt(2x)*sqrt(20y) = 4y*sqrt(x)*sqrt(10y) = 4y*sqrt(10xy)
its 2 times 2 equals ┴¥
4
In real numbers there is no square root of -4x2 However, when using complex numbers where √-1 = i, then: √-4x2 = 2xi If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving: y2 - 4x2 = (y + 2x)(y - 2x)
2x(square root of 57) If we approximate this, it is about 15.1 but the first answer is exact and in simplest form.
It depends entirely on the value of x.