Natural numbers must not contain negative numbers or fractions.
Therefore, the square root of 3 = 1.73205080757 is not a natural number
it depends on the number, for example the square root of nine is a natural number. it's 3. the square root of 3 is not a natural number. It is 1.73... and it goes on and on.
No, the square root of 21 is not a natural number. Natural numbers are positive integers (1, 2, 3, ...), and the square root of 21 is approximately 4.58, which is not an integer. Therefore, it does not qualify as a natural number.
Yes. For example, 3 is the [principal] square root of 9.
No, the square root of 5 is not a natural number. Natural numbers are the set of positive integers (1, 2, 3, ...), and the square root of 5 is an irrational number, approximately 2.236, which cannot be expressed as a simple fraction or a whole number.
The square root of a number is a number which, when multiplied by itself, gives the original number. So, 9 has a square root which is 3 because 3*3 = 9
it depends on the number, for example the square root of nine is a natural number. it's 3. the square root of 3 is not a natural number. It is 1.73... and it goes on and on.
No, the square root of 21 is not a natural number. Natural numbers are positive integers (1, 2, 3, ...), and the square root of 21 is approximately 4.58, which is not an integer. Therefore, it does not qualify as a natural number.
Yes. For example, 3 is the [principal] square root of 9.
No, the square root of 5 is not a natural number. Natural numbers are the set of positive integers (1, 2, 3, ...), and the square root of 5 is an irrational number, approximately 2.236, which cannot be expressed as a simple fraction or a whole number.
It is none of those because the square root of -9 is an imaginary number but the square root of 9 is 3 which is a rational integer or whole number
If the square root of a natural number is not an integer, then it is irrational. Another way to look at it: if a natural number N falls between two perfect squares, then the square root of N is irrational.So in this case, 12 is between 9 (3 squared) and 16 (4 squared). So the square root of 12 is between 3 and 4, and also the square root of 12 is irrational.
Yes, the square root of 3 is a real number. (It is not imaginary. The square root of a negative number is imaginary.) The square root of 3 is not a rational number. It cannot be written as a fraction.
The number 3 is the square root of the number 9 !
The square root of -3 is an imaginary number and the square root of 3 is an irrational number that can't be expressed as a fraction
The square root of a number is a number which, when multiplied by itself, gives the original number. So, 9 has a square root which is 3 because 3*3 = 9
the square root of a number is the number that is multiplied by itself to get that number, for example the square root of 9 is 3
You can't write that as an exact fraction. In general, the square root of a natural number is either a natural number, or an irrational number - i.e., one that can't be written as a fraction. Of course, you can approximate it; for example (as a mixed fraction) as 3 74/100, or as 3 3/4.