No, an irrational number is, in simple terms, a number that keeps repeating. The square root of 4 is positive or negative 2, which does not repeat and is therefore rational.
The square root of 4 is 2 which is a rational number
The square root of 3 is an irrational number
Yes, the square root of a whole number is either an integer or an irrational number. If the whole number is a perfect square (like 0, 1, 4, 9, etc.), its square root is an integer. However, if the whole number is not a perfect square (like 2, 3, 5, etc.), its square root is an irrational number.
Yes, the square root of 48 is an irrational number. This is because 48 can be simplified to (4 \times 12), and since the square root of 4 is a whole number (2), we can express (\sqrt{48}) as (2\sqrt{12}). The square root of 12, however, is not a perfect square and cannot be simplified to a whole number, making (\sqrt{48}) irrational.
The square root of 680 is an irrational number and it is about 26.0768 rounded to 4 decimal places
[ square root of (4.1) ] is irrational. But [ square root of (4) ] is rational.
The square root of 4 is 2 which is a rational number
It is rational. The root of a perfect square, such as 4, is rational; the root of any positive integer that is not a perfect square is an irrational number.
The square root of 3 is an irrational number
The square root of -4 is not irrational, it is imaginary. Irrational numbers are numbers that cannot be expressed as a fraction, like the square root of 2. Irrational numbers, however, are a subset of real numbers. The square root of -4 however, is not even a real number because no real number, when squared, gives -4. Therefore the square root of -4 is an imaginary number.In calculus, the root is expressed as 2i where iis the square root of -1.
The square root of 16 is 4 which is a rational number
The square root of a composite number is not always an irrational number. e.g. 4 is a composite number and its square root is 41/2 = 2, which is rational number.
Not always as for instance the square root of 16 is 4 which is a rational number but the square root of 2 is an irrational number.
It's irrational/not a real number
The square root of 3 is an irrational number
The square root of 16 is 4, which is a rational number.
If the square root of a natural number is not an integer, then it is irrational. Another way to look at it: if a natural number N falls between two perfect squares, then the square root of N is irrational.So in this case, 12 is between 9 (3 squared) and 16 (4 squared). So the square root of 12 is between 3 and 4, and also the square root of 12 is irrational.