The square root of 4 is 2 which is a rational number
The square root of 3 is an irrational number
The square root of 680 is an irrational number and it is about 26.0768 rounded to 4 decimal places
Sqrt(-4) is an irrational number therefore we must use i. i=sqrt(-1) allows us to pull i out of sqrt(-4): sqrt(4)*i leaves us with 2i The square root of -4 is NOT an irrational number but an imaginary number.
The square roots of 16 are +4 and -4. Both of them are rational numbers.
[ square root of (4.1) ] is irrational. But [ square root of (4) ] is rational.
The square root of 4 is 2 which is a rational number
It is rational. The root of a perfect square, such as 4, is rational; the root of any positive integer that is not a perfect square is an irrational number.
The square root of 3 is an irrational number
The square root of 16 is 4 which is a rational number
The square root of 16 is 4 which is a rational number
The square root of -4 is not irrational, it is imaginary. Irrational numbers are numbers that cannot be expressed as a fraction, like the square root of 2. Irrational numbers, however, are a subset of real numbers. The square root of -4 however, is not even a real number because no real number, when squared, gives -4. Therefore the square root of -4 is an imaginary number.In calculus, the root is expressed as 2i where iis the square root of -1.
The square root of a composite number is not always an irrational number. e.g. 4 is a composite number and its square root is 41/2 = 2, which is rational number.
Not always as for instance the square root of 16 is 4 which is a rational number but the square root of 2 is an irrational number.
It's irrational/not a real number
The square root of 3 is an irrational number
The square root of 16 is 4, which is a rational number.