NO!!!
The square root of '65' is between 8 & 9.
Remember 8^2 = 64 & 9^2 = 81
By Trial and Error
8.1^(2) = 65.61
8.05^(2) = 64.8025
8.06^(2) = 64.9636
8.065^(2) = 65.044225
8.064^(2) = 65.028096
8.063^(2) = 65.65.0119...
8.062^(2) = 64.9958...
8.0622^(2) = 64.999...
8.06225^(2) = 64.99987...
8.062255^(2) = 64.99995569 ~ 65
Hence the Square Root of '65' is 8.062255 ... To 5 d.p.
The square root of 50 is between 7 and 8
The square root of 421.875 is 7.5 The square root of 7.5 is 2.7386128
Square root of 8 = 2.82842712 It is clear from the value that it doesn't lie between 7 and 9.
The square root of eight is in between the square root of 7 and the square root of 9, which equals 3.
The square root of 49 is 7 and the square root of 64 is 8 so it has to be between 7 and 8 (and it's probably closer to 7)
No, between 8 and 9, very close to eight.
The square root of 49 is 7. The square root of 64 is 8. The square root of any number between 49 and 64 is between 7 and 8.
The square root of 49 is 7. The square root of 64 is 8. The square root of any number between 49 and 64 is between 7 and 8.
The square root of 36 is 6 and the square root of 49 is 7 - exactly and not between
The square root of 49 is +7 OR -7 So the answers are -65/6 and 71/6 or -6.8333... and 7.1666...
The square root of 50 is between 7 and 8
The square root of 421.875 is 7.5 The square root of 7.5 is 2.7386128
7 is the square root of 49 and 8 is the square root of 64.
Square root of 8 = 2.82842712 It is clear from the value that it doesn't lie between 7 and 9.
3 * sqrt(14)
The square root of eight is in between the square root of 7 and the square root of 9, which equals 3.
The square root of 147 is 7 square root 3. You determine this by writing 147 as a product of prime numbers or (3 * 7 * 7). The square root of (7 * 7) is 7 leaving the 3 inside the radicle symbol. somewhere between 12.12 and 12.13