No. A number will have a rational square root, only if both the numerator and denominator of the simplified fraction are squares of integers.
All integers are rational, because they can be written in the form x / 1, where "x" is the integer.
Well, for example, the square root of 4 is 2, which is a rational number. As long as the number which is being square rooted is not a square number itself (i.e. 1, 4, 9, 16 etc.), then it will be irrational. So..... the square roots of 49, 100, 196, for example, are all rational numbers (7, 10 and 14 respectively.) They do not have to be integers. The square of of any rational number automatically has a rational square root eg the square root of 77.41792 is 77.4179 . Rational means expressable as a ratio of integers: 77.4179 is 774179/10000 .
The square root of four is a real number because it is a non-negative number that can be expressed on the number line. It is also a rational number because it can be expressed as the fraction 2/1. In fact, it is both a real number and a rational number, as all rational numbers are also real numbers.
It is all of them except for irrational.
Yes because the square root of 4 is 2 which is a rational number
No. Lots of square roots are not rational. Only the square roots of perfect square numbers are rational. So for example, the square root of 2 is not rational and the square root of 4 is rational.
The square root of any positive square number is always rational as for example the square root of 36 is 6 which is a rational number.
Yes. The square root of 81 is 9 - a natural number and all natural numbers are rational numbers.
Oh, dude, the square root of 25 is 5, which is a whole number and can be expressed as a fraction 5/1. So, yes, it is a rational number because it can be written as a ratio of two integers. But hey, who really cares about all that math stuff anyway, right?
The square root of 13 is irrational. All square roots of whole numbers are irrational unless the number is a perfect square.
Yes, of some; the square root of any perfect square is rational - for example, the square root of 4, of 9, of 16, etc.On the other hand, if your "composite number" is not a perfect square, then its square root is irrational.
No. A number will have a rational square root, only if both the numerator and denominator of the simplified fraction are squares of integers.
All integers are rational, because they can be written in the form x / 1, where "x" is the integer.
The square root of 97 is an irrational number. This is because the square root of 97 cannot be expressed as a fraction of two integers. In other words, the decimal representation of the square root of 97 goes on forever without repeating, making it an irrational number.
Well, for example, the square root of 4 is 2, which is a rational number. As long as the number which is being square rooted is not a square number itself (i.e. 1, 4, 9, 16 etc.), then it will be irrational. So..... the square roots of 49, 100, 196, for example, are all rational numbers (7, 10 and 14 respectively.) They do not have to be integers. The square of of any rational number automatically has a rational square root eg the square root of 77.41792 is 77.4179 . Rational means expressable as a ratio of integers: 77.4179 is 774179/10000 .
The square root of four is a real number because it is a non-negative number that can be expressed on the number line. It is also a rational number because it can be expressed as the fraction 2/1. In fact, it is both a real number and a rational number, as all rational numbers are also real numbers.